To calculate dead and live load for industrial steel structures and to apply them using TSD
- Brick wall load = 0.15 x 20x 5.2 = 15.6 kN/m^2 (Ground to intermediate floor)
- Brick wall load = 0.15 x 20x6.8 = 20.5 kN/m^2 (Intermediate to roof)
- Brick wall load = 0.15 x 20x14.5 = 14.5 kN/m^2 (Roof to top )
- Roof load = 1.5 kN/m
- Ceiling load = 0.3 kN/m
Procedure:
- Now open Tekla structural designer software
- Open the week 3 file where we have created a steel structure
- Now go to model tab and select slabs on beams option
- Now add slabs to each floor
- Now go to load tab and select load cases and add required loads
- Now select load combinations and add what required
- Select the level we want to apply loads on
- Select the loads required from the list
- Now goto select the area to apply load on slab
- Go to load tab and select UDL to apply on brick walll
- Apply loads on the roof as well
Aim: To Calculate live load in design report based on IS code and apply live load on the model
Procedure:
Based on the IS 875 the live loads are applied, as follows.
- Workshop = 5
</math>">kN/m2k n m 2 - Staircase =5
</math>">kN/m2k n m 2 - Corridor = 5
</math>">kN/m2k n m 2 - Meeting Room = 5
</math>">kN/m2k n m 2 - Store Room =5
</math>">kN/m2k n m 2 - Toilet = 2
</math>">knN/m2k n m 2 - Canteen = 3
</math>">kN/m2k n m 2 - Office Room = 3
</math>">kN/m2k n m 2 - Conference Room = 5
</math>">kN/m2k n m 2 - Equipment Room = 10
</math>">kN/m2k n m 2 - Rest Room = 2
</math>">kN/m2k n m 2 - Administration Room = 5
</math>">kN/m2k n m 2
The Live loads are applied for all the floors, as shown below.
- Now select the level where we want to apply the loads
- Now select the loads as required at the bottom left corner
- Now go to the load tab and select the Area to apply load on the slab
- Now we can see the Area load applied on the slab
Result:
Calculation of live load in design report based on IS code and application of live load on the model is done.
Aim: Generate a calculation for 5T crane loading based on the following inputs
Procedure:
Given Data:
- Centre to Centre of wheel = 10m
- Weight of crab = 40 KN
- Number of wheels = 4
- Wheelbase = 2m
- Crane Capacity=50 KN
- weight of trolley = 10kN
- hook approach = 1m
Maximum point load on Crane=Crane capacity + weight of the trolley
=50+10
=60KN
UDL=
=40/14
=2.89KN/m
Moment at A:
=60x1-RBX14+2.89X14X14/2
RB=24.5KN
RA+RB-60-2.89X14=0
RA=60+2.89X14-RB
RA=75.9KN
Now assuming self weight of gantry grider=1.2 KN/m
assuming self weight of gantry grider=0.3KN/m
Total self weight=1.2+0.3
=1.5KN/m
FACTORED LOAD=1.5X1.5
=2.25KN/m
Now load on each wheel=75.9/2
=37.97KN
Factored load=37.97x1.5
=56.95KN
=57KN
Moment at C:
RDx6=2.25x6x6/2+57x4.5+57x2.5
RD=73.25KN
RC+RD-57-57-2.25X6
RC+RD=127.5KN
RC+73.25=127.5
RC=127.5-73.25
RC=54.25KN
MAX SHEAR FORCE
REX6-57-57X4-2.25X6X6/2=0
RE=101.75KN
IMPACT LOAD:
=10% OF WHEEL LOAD
=0.1X101.75
=10.175KN
V=Wl/2
=
=4.5KN
Max shear force=4.5+10.175+101.75
=116.425KN
Lateral load analysis=5% of total weight
=
=3KN
Result: With this our work is done