Challenge

Section Modulus calculation and optimization

SECTION MODULUS

It is the ratio of moment of intertia and the distance of the topmost or the bottommost fiber from the neutral axis.

S=I/Y

S= Section modulus

I= Moment of inertia

Y= Distance between the netural axis and the extreme end of the object.

Example:

A sectio of a car hood to check its section modulus.

Case-01

Section of modulus= I/Y

= 4.8136/486.94

Section of modulus = 9.884x10^-3

Case-02

Increasing the overall distance by 2 mm

Section of modulus = I/Y

= 6.4192/490.96

Section of modulus = 13.074x10^-3

As we see Section of modulus is high in case-02, because as you increase the overall distance the moment of inetia also increases.

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