Section Modulus calculation and optimization

SECTION MODULUS:-

The section modulus (S) is geometric property of the cross section used for designing beams and flexural members. It does not represent anything physically.

Formula of Section Modulus: It may be defined as the ration of total moment resisted by the section to the stress in the extreme fibre which is equal to yield stress.

There fore,

S=I/Y Where,

S = Section modulus (mm^3)

I = Moment of Inertia of the section about the bending axis. (mm^4)

Y = Distance between the neutral axis and extreme end of the object (mm)

Calculation part:-

IN case 1:

AS we know that by using moment inertia command we get the max and min value moment of inertia & we will take the min value that is;

I=6.832 x 10^5mm^4 &

Y=479.788/2

=239.894mm

There fore,

S=I/Y=2847.9245mm^3

CASE 2:-

For case 2 we do the same thing as case 1 but we change the sectional area by offsetting it to 0.5mm

SINCE the Y remains same,

S=7.187 x 10^5mm^4/239.894mm=2995.9mm^3

CONCLUSION:-

Hence when comparing case 1 & case 2,

1. The section modulus value of case 2 is higher than the case 1

2. As we increase the section area, the moment of inertia & section modulus increases which means strength and load material also increases.