Section Modulus calculation and optimization

SECTION MODULUS

I got moment of inertia (Max & Min) values of hood part.

MOI (max) = 0.168 (kg x m^2)

MOI (min) = 0.041 (Kg x m^2 )

Total distance of the hood y = 1539.5 mm

Distance between the neutral axis to the external end = (1539.5/2) = 769.75 mm

To calculate S(max) and S(min)

Section modulus is the ratio of second moment of area and distance from neutral axis to the extreme end is given by S

S=I/Y

S(max) = I(max)/Y = (2.097e+006 (Kg x mm^2 )/ 769.75 mm) = 2724.26 kg x m

S(min) = I(min)/Y = (508921.1 (kg x mm^2)/ 769.75 mm) = 661.15 kg x m