Challenge

Project 2 - Rankine cycle Simulator

% Rankine Cycle Simulator

close all

clc

% Printing Introduction

fprintf('RANKINE CYCLE SIMULATOR')

fprintf('1-2 is isentropic expansion in the Turbine')

fprintf('2-3 is Constant Pressure Heat Rejection by the Condenser')

fprintf('3-4 is isentropic Compression in pump')

fprintf('4-1 is Constant Pressure Heat Addition by the Boiler')

% User Inputs

P1 = input('Enter the Pressure at the Turbine Inlet (in bar):');

T1 = input('Enter the Temprature at the Turbine Inlet (in Degree Celcius):');

P2 = input('Enter the Pressure at the Turbine Outlet (in bar):');

% State point 1

H1 = XSteam('h_pt',P1,T1); %Enthalpy

S1 = XSteam('s_pt',P1,T1); %Entropy

Hf1 = XSteam('hL_p',P1); %Enthalpy of saturated liquid

Hg1 = XSteam('hV_p',P1); %Enthaply of saturated vapour

Ts1 = XSteam('Tsat_p',P1); %Saturation Temprature

Sf1 = XSteam('sL_p',P1); %Entropy of saturated liquid

Sg1 = XSteam('sV_p',P1); %Entropy of saturated vapour

% State point 2

S2 = S1;

Sf2 = XSteam('sL_p',P2);

Sg2 = XSteam('sV_p',P2);

x = (S2-Sf2)/(Sg2-Sf2); % Dryness fraction

Hf2 = XSteam('hL_p',P2);

Hg2 = XSteam('hV_p',P2);

H2 = Hf2 + x*(Hg2-Hf2);

T2 = XSteam('T_ph',P2,H2);

Ts2 = XSteam('Tsat_p',P2);

% State point 3

H3 = Hf2;

S3 = Sf2;

T3 = T2;

P3 = P2;

% State point 4

P4 = P1;

S4 = S3;

H4 = XSteam('h_ps',P4,S4);

T4 = XSteam('T_ps',P4,S4);

t = linspace(0,374,500); % temp space for plotting saturation cutves

%Plot T-S Diagram

figure(1)

hold on

% Plot Saturation Curve

for i = 1 : length(t)

plot(XSteam('sL_T',t(i)),t(i),'.','color','b')

plot(XSteam('sV_T',t(i)),t(i),'.','color','b')

end

% Plot Cycle

plot([S1 S2],[T1 T2],'linewidth',2,'color','r')

if x>1

T3 = Ts2;

plot([S2 Sg2 S3 S4],[T2 Ts2 T3 T4],'linewidth',2,'color','r')

T2 = Ts2;

else

plot([S2 S3 S4],[T2 T3 T4],'linewidth',2,'color','r')

end

l = linspace(T1,T2,1000);

for i = 1 : length(l)

plot(XSteam('s_pT',P1,l(i)),l(i),'.','color','r')

end

plot([Sf1 Sg1],[Ts1 Ts1],'linewidth',2,'color','r')

xlabel('Entropy[KJ/Kg-K]')

ylabel('Temprature[K]')

title('T-S Diagram')

% Plot H-S Diagram

figure(2)

hold on

% Plot Saturation Curve

for i = 1 : length(t)

plot(XSteam('sL_T',t(i)),XSteam('hL_T',t(i)),'.','color','b')

plot(XSteam('sV_T',t(i)),XSteam('hV_T',t(i)),'.','color','b')

end

% Plot Cycle

plot([S1 S2 S3 S4 S1],[H1 H2 H3 H4 H1],'linewidth',2,'color','r')

xlabel('Entropy[KJ/Kg-K]')

ylabel('Enthalpy[KJ/Kg]')

title('H-S Diagram')

% calculations

% Turbine Work

Wt = H1-H2;

% Pump Work

Wp = H4-H3;

% Heat Addition

Qin = H1-H4;

% Heat Rejection

Qout = H2-H3;

% Net Work

Wnet = Wt-Wp;

% Efficiency

Ntherm = (Wnet/Qin)*100;

% Specific steam consumption

SSC = 3600/Wnet;

% Back Work Ratio

BWR = Wp/Wt;

% Print Results

fprintf('Results')

fprintf('At State Point 1:')

fprintf('P1 is : %.2f bar',P1)

fprintf('T1 is : %.2f Deg Celcius',T1)

fprintf('H1 is : %.2f KJ/Kg',H1)

fprintf('S1 is : %.2f KJ/Kg-K',S1)

fprintf('\\nAt State Point 2:')

fprintf('P2 is : %.2f bar',P2)

fprintf('T2 is : %.2f Deg Celcius',T2)

fprintf('H2 is : %.2f KJ/Kg',H2)

fprintf('S2 is : %.2f KJ/Kg-K',S2)

fprintf('\\nAt State Point 3:')

fprintf('P3 is : %.2f bar',P3)

fprintf('T3 is : %.2f Deg Celcius',T3)

fprintf('H3 is : %.2f KJ/Kg',H3)

fprintf('S3 is : %.2f KJ/Kg-K',S3)

fprintf('\\nAt State Point 4:')

fprintf('P4 is : %.2f bar',P4)

fprintf('T4 is : %.2f Deg Celcius',T4)

fprintf('H4 is : %.2f KJ/Kg',H4)

fprintf('S4 is : %.2f KJ/Kg-K',S4)

fprintf('\\nWt is : %.2f KJ/Kg',Wt)

fprintf('Wp is : %.2f KJ/Kg',Wp)

fprintf('Wnet is : %.2f KJ/Kg',Wnet)

fprintf('Thermal Efficiency is : %.2f percent',Ntherm)

fprintf('S.S.C. is : %.2f Kg/KWh',SSC)

fprintf('Back Work Ratio is : %.3f',BWR)

#COMMAND WINDOW

RANKINE CYCLE SIMULATOR1-2 is isentropic expansion in the Turbine2-3 is Constant Pressure Heat Rejection by the Condenser3-4 is isentropic Compression in pump4-1 is Constant Pressure Heat Addition by the BoilerEnter the Pressure at the Turbine Inlet (in bar):44
Enter the Temprature at the Turbine Inlet (in Degree Celcius):538
Enter the Pressure at the Turbine Outlet (in bar):5.83
ResultsAt State Point 1:P1 is : 44.00 barT1 is : 538.00 Deg CelciusH1 is : 3528.83 KJ/KgS1 is : 7.15 KJ/Kg-K\nAt State Point 2:P2 is : 5.83 barT2 is : 157.71 Deg CelciusH2 is : 2920.82 KJ/KgS2 is : 7.15 KJ/Kg-K\nAt State Point 3:P3 is : 5.83 barT3 is : 157.71 Deg CelciusH3 is : 665.64 KJ/KgS3 is : 1.92 KJ/Kg-K\nAt State Point 4:P4 is : 44.00 barT4 is : 158.16 Deg CelciusH4 is : 669.84 KJ/KgS4 is : 1.92 KJ/Kg-K\nWt is : 608.01 KJ/KgWp is : 4.20 KJ/KgWnet is : 603.81 KJ/KgThermal Efficiency is : 21.12 percentS.S.C. is : 5.96 Kg/KWhBack Work Ratio is : 0.007>>

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