Challenge

Section Modulus calculation and optimization

Section Modulus calculation and optimization

Introduction

SECTION MODULUS

  • Section modulus is the ratio of total moment resisted by the section to the stress in the extreme fibre.
  • Section modulus give us idea about how much of load the given structure can take.
  • If the section modulus increases the moment of resistance increases and hence its load bearing capacity.
  • S=I/Y ,

Where S= section modulus

I=moment of inertia of a section

Y=distance from neutral axis to any given fiber.

CASE 1

Hood design

Moment of inertia (max)=4.78578`*10^4mm^4

Moment of inertia(min)=1.88739⋅104mm41.88739⋅104��4

value of y=440mm

`section modulus=Moi (min)/`

1.88739⋅1041.88739⋅104/ 440

=42.89mm^3

CASE 2

hood optimised design

by adding +0.6 mm in the depth of hood

MOI (max) = 7.46052`*10^4 mm^4

MOI (MIN)= 2.94221*10^4 mm^4

s=66.89 mm^3

comparing case 1 and 2

percentage increase in optimised one= (66.89-42.89)/42.89 = 5.5%

CONCLUSION

  • By comparing the values we can clearly say that the section modulus of the optimized hood increases by 5.5%
  • moment of inertia increases by increasing depth of hood.
  • it seems if we increase the gap between inner and outer panel also increases.
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