Challenge

Section Modulus calculation and optimization

ANSWER:

SECTION MODULE:

SECTION MODULE IS A GEOMENTRY PROPERTY FOR A GIVEN CROSS SECTION USED IN THE DESIGN OF BEAMS OR FTEXTURE MEMBERS.OTHER GEOMENTRIC PROPETIES USED IN DESIGN INCLUDE AREA FOR TENSION AND SHEAR, RADIUS OF GYRATION FOR COMPERESSION, AND SECOND MOMENT OF AREA AND POLAR SESONG MOMENT OF AREA FOR STIFFNESS.THE SECTION MODULE OF THE CROSS SECTIONAL SHAPE IS OF SIGNIFICANT IMPORTANCEIN DESIGNING BEAMS.IT IS A DIRECT MEASURE OF THE STRENGTH OF THE BEAM.A BEAM THAT HAS A LARGE SESTION MODULUS THAN ANOTHER WILL BE STRONGER AND CAPABLE OF SUPPORTING GREATER LOADS.SECTION MODULE IS A RATION OF MOMENT OF INERTIA (I) OF THE BEAM CROSS SECTION ABOUT THE NETRUAL AXIS.

S=I/Y

HERE;

S = SECTION MODULUS

I = MOMENT OF INERTIA(unit mm^4)

Y = DISTANCE FROM NETURAL AXIS TO THE EXTREME END(UNIT mm)

ELASTIC SECTION MODULUS:

THE ELASTIC SECTION MODULUS IS DEFINED AS THE RATIO OF THE SECOND MOMENT OF AREA(OR MOMENT OF INERTIA)AND THE DISTANCE FROM THE NETURAL AXIS TO ANY GIVEN(OR EXTREME)FIBER.IT CAN ALSO BE DEFINED IN TERMS OF THE FIRST MOMENT OF AREA.WHEREAS SECTION MODULUS IS GEOMENTRIC PROPERTY AND IS THE RATIO OF MOMENT OF INERTIA TO DISTANCE OF NETURAL FIBER FROM NETRUAL AXIS

CALCULATION:

MOI = MOMENT OF INERTIA

E = YOUNGS MODULUS

I = AREA OF MOMENT OF INERTIA

OPTIMATION

MOI(max) =1.0.32876684e+07(mm^4)

MOI(min) =5.458803993E+04(mm^4)

S = I/Y

I = MOI(min)

y = TOTAL DISTANCE/2

Y = 899.5/2=499.75

S = 5.458803*10^3mm/499.75

S = 10.9230mm^3

conclusion:

IT CONCLUDE THE SECTION MODULE OF THE HOOD LOW AND IT CASE LOW DAMAGE IN ACCIDENT FOR WHO HITTING ZONE ADULT OR CHILD AND THE CAR

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