Challenge

Project on Concrete Mix Design for various grades of Concrete

Mix Proportion by weight of M35 grade of concrete with fly ash is 1:2.08:2.72 and its water-cement ratio was found to be 0.4. Mix Proportion by weight of M50 grade of concrete without fly ash is 1:2.28:3.12 and its water-cement ratio was found to be 0.44.

Mix Design for M35 Grade Concrete with Fly ash1) Stipulations for Proportioninga) Grade designation: M35b) Type of cement: OPC 53 grade conforming toIS-12269-1987c) Type of mineral admixture: Fly ash conforming to IS 38I2 (Part I)d) Maximum nominal size of aggregate: 20mme) Minimum cement content: 320 kg/m'f) Maximum water-cement ratio: 0.45g) Workability:50-75 mm (Slump)h) Exposure condition:Severe(for reinforced concrete)i) Method of concrete placing: Pumpingj) Degree of supervision: Goodk) Type of aggregate: Crushed angular aggregatel) Maximum cement (OPC) content:450 kg/m3m) Chemical admixture type:Super plasticizer confirming to IS-91032) Test Data of materials:a) Cement used: OPC 43 grade conforming to IS 8112b) Specific gravity of cement: 3.15c) Fly ash: conforming to IS 38I2 (Part I)d) Specific gravity of fly ash: 2.2e) Chemical admixture: Super plasticizer conforming to IS 9103f) Specific gravity ofI) Coarse aggregate: 2.742) Fine aggregate: 2.74g) Water absorption1) Course aggregate: 0.5%

The mix design M-50 grade (Using Admixture –Sikament) provided here is for reference purpose only. Actual site conditions vary and thus this should be adjusted as per the location and other factors.

Parameters for mix design M50

Grade Designation = M-50
Type of cement = O.P.C-43 grade
Brand of cement = Vikram ( Grasim )
Admixture = Sika [Sikament 170 ( H ) ]
Fine Aggregate = Zone-II

Sp. Gravity
Cement = 3.15
Fine Aggregate = 2.61
Coarse Aggregate (20mm) = 2.65
Coarse Aggregate (10mm) = 2.66

Minimum Cement (As per contract) =400 kg / m3
Maximum water cement ratio (As per contract) = 0.45

Mix Calculation: –

1. Target Mean Strength = 50 + ( 5 X 1.65 ) = 58.25 Mpa

2. Selection of water cement ratio:-
Assume water cement ratio = 0.35

3. Calculation of water: –
Approximate water content for 20mm max. Size of aggregate = 180 kg /m3 (As per Table No. 5 , IS : 10262 ). As plasticizer is proposed we can reduce water content by 20%.

Now water content = 180 X 0.8 = 144 kg /m3

4. Calculation of cement content:-
Water cement ratio = 0.35
Water content per cum of concrete = 144 kg
Cement content = 144/0.35 = 411.4 kg / m3
Say cement content = 412 kg / m3 (As per contract Minimum cement content 400 kg / m3 )
Hence O.K.

5. Calculation for C.A. & F.A.: [ Formula’s can be seen in earlier posts]-

Volume of concrete = 1 m3
Volume of cement = 412 / ( 3.15 X 1000 ) = 0.1308 m3
Volume of water = 144 / ( 1 X 1000 ) = 0.1440 m3
Volume of Admixture = 4.994 / (1.145 X 1000 ) = 0.0043 m3
Total weight of other materials except coarse aggregate = 0.1308 + 0.1440 +0.0043 = 0.2791 m3

Increasing cement, water, admixture by 2.5% for this trial

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