Project on Concrete Mix Design for various grades of Concrete

Mix Design for M35 grade concrete with fly asConcrete

This section has Specifications of the materials and requirements of the concrete to be made

• Grade Designation = M35
• Type of Cement = OPC 53
• Type of Admixturev= Fly ash
• Maximum NominalSize ofAggregate = 20mm
• Minimum Cement Content =340kg Table 5-IS456
• Maximum Cement Content = 450kg Table 5-IS456
• Partial replacement of cement by Fly ash 30%as per requirement
• Maximum W/C ratio= 0.45 Table 5-IS456
• Workability= 100mm
• Chemical Admixture = PCS Type

II. TEST DATA FOR MATERIALS

Standard values are assumed below.
• Cement = OPC 53
• Specific Gravity of Cement = 3.15
• Mineral Admixture = Fly ash
• Specific Gravity of Fly ash = 2.9
• Chemical [email protected]% IS9103
• Specific Gravity of
Coarse Aggregate = 2.74
Fine Aggregate = 2.74
Admixture PCE based = 1.12
• Water Absorption Test
Coarse aggregate = 0.5 %
Fine aggregate = 1 %H

III. TARGET STRENGTH FOR MIX PROPORTIONS OF M35 GRADE CONCRETE

Table 1 of IS456

Fck= fck+1.65s

“S” from Table1-IS10262

Fck= 35+1.65×5Fck= 43.25 N/mm2

IV. SELECTION OF WATER-CEMENT RATIO

Maximum W/C ratio=0.45 Table 5-IS456

Adopted W/C ratio=0.45

V. SELECTION OF WATER CONTENT

Maximum Water Content =186 L

(Table 2-IS1026 Above water-content is for 25 to 50mm slump)

But we need 100mm slump for our concert as per specification

Increase the water-content to get the required slump

Clause 4.2 of IS1026 suggests to increases 3% of water-content to get an extra 25mm slump

Hence we to increase water content by 6% to get an additional 50mm slump for our concrete

Water-content for 100mm Slump
=186+(0.06*186)
=197.16 L

Amount of water-content to be reduced depends on the type of superplasticizer

Percentage of Reduction in water content
=20% Water content requirement

=198 – (0.20*198)
=157.73
Adopted Water Content =160 L

VI. CALCULATION OF CEMENT AND FLY ASH CONTENT

Adopted Water Cement Ratio=0.45

Total Cementitious (Cement +Fly ash) requirement= Water Content / WaterCement ratio
=160/0.45=355.55 kg

we have increased the cementitious content by 10%.

Final Cementitious
Content (Cement+Fly ash)
= 356*1.10
=391.6 kg

Minimum Cement Content required for ‘severe’ exposure=340kg Table 5-IS456
Adopted
Cementious content=391.6 kg> 340kg

Fly ash content requirement= 391.6 * 0.3030% replacement
= 117.48 ~ 118 kg

Cement Content requirement=Cementious content – Flyash
=391.6-117.48
= 274.12

Calculation of Super Plasticiers @ 0.6 percent to the mass of cementitious content
= 391.6*(0.6/100)
= 2.35 kg

VII COARSE AND FINE AGGREGATE

Coarse Aggregate ratio
= 0.62 Table3-IS10262
(For W/C =0.5))

Coarse Aggregate ratio for 0.45 w/c ratio
= 0.63(adding 0.01 for every decrease .05 and vice versa)

Final Fine Aggregate ratio
= 0.37(1-0.63) = 0.37

VIII MIX CALCULATIONS OF M35 GRADE CONCRETE

A)Volume e of Concrete= 1 cu.m

B) total Volume of Cement= Cement/(S.G*1000)

= 275/(3.15*1000)
= 0.087 cu.m

C)Total Volume of Fly ash= Flyash/(S.G*1000)

= 118/(2.5*1000)
= 0.041 cu.m

D)Volume of Water=Water /(S.G*1000)

= 160/(1*1000)
= 0.160 cu.m

E)Volume of Superplasticizers= Superplasticizers /(S.G*1000)

= 2.35/(1.12*1000)
= 0.002 cu.m

F)Total Aggregates requirement= A – (B+C+D+E)

= 1 -(0.087 +0.041+0.160+0.002)
= 0.71 cu.m

G)Coarse Aggregate (C.A)= F * C.A ratio * S.G * 1000

= 0.71*0.63 *2.74 *1000
= 1225.6 kg

H) Fine Aggregate (F.A) = F * F.A ratio * S.G * 1000

= 0.71*0.37*2.74 *1000
=719.8 kg

Cement Flyash Sand Aggregate Water and Superplasticizer needed for M35 grade concrete

MATERIALSQUANTITY

• Cement = 275 kg
• Flyash= 118 kg
• Fine Aggregate= 720 kg
• coarse Aggregate (20mm) = 1226 kg
• Water = 160 L
• PCE based SuperPlasticizer = 2 L

To find the design mix ratio divide the calculated value of all materials by the weight of cement

Mix Ratio of M35 Grade concrete by weight is
Cement : Flyash: F.A : C.A : Water =1:0.4:2.6:4.46:0.58

Mix Design for M50 grade concrete without fly asConcrete

This section has Specifications of the materials and requirements of the concrete to be made

• Grade designation : M 50
• Type of cement : OPC 53 grade
• Maximum nominal size of aggregate : 20 mm
• Minimum cement content : 360 kg/m3 Table 5-IS456
• Maximum water-cement ratio : 0.35 Table 5-IS456
• Workability : 100mm
• Maximum cement content : 450 kg/m3 Table 5-IS456
• Chemical admixture type : Super Plasticizer

II. TEST DATA FOR MATERIALS

• Cement = OPC 53
• Specific gravity of cement : 3.12
• Specific gravity of Coarse Aggregate : 2.74
• Specific gravity of Fine Aggregate : 2.56
• Water Absorption Coarse aggregate = 0.5 %
• Water Absorption Fine aggregate = 1 %H

III. TARGET STRENGTH FOR MIX PROPORTIONS OF M50 GRADE CONCRETE

ftarget = fck + 1.65 x s

“S” from Table1-IS10262 standard deviation,

s = 5.0 N/mm2

ftarget = 50 + 1.65 x 5.0 = 58.25 N/mm2

IV. SELECTION OF WATER-CEMENT RATIO

Maximum water-cement ratio = 0.35 Table 5 of IS 456 : 2000

V. SELECTION OF WATER CONTENT

Maximum Water Content =186 L

(Table 2-IS1026 Above water-content is for 25 to 50mm slump)

But we need 100mm slump for our concert as per specification

Increase the water-content to get the required slump

Clause 4.2 of IS1026 suggests to increases 3% of water-content to get an extra 25mm slump

Hence we to increase water content by 6% to get an additional 50mm slump for our concrete

Water-content for 100mm Slump
=186+(0.06*186)
=197.16 L

Amount of water-content to be reduced depends on the type of superplasticizer

Based on trials with Super plasticizer water content reduction of 27% has been achievedwater content
= 197 – [197 x (27/100)]
= 143 litres.

VI. CALCULATION OF CEMENT

Water-cement ratio = 0.35

Cement content = 143/0.35
= 410 kg/m3

From Table 5 of IS 456

minimum cement content for ‘Extreme exposure’ condition = 360 kg/m3

410 kg/m3 > 360 kg/m3
hence, O.K.

VII COARSE AND FINE AGGREGATE

Coarse Aggregate ratio
= 0.62 Table3-IS10262
(For W/C =0.5))

Coarse Aggregate ratio for 0.45 w/c ratio
= 0.63(adding 0.01 for every decrease .05 and vice versa)

Final Fine Aggregate ratio
= 0.37(1-0.63) = 0.37

Therefore,

Volume of coarse aggregate = 0.65 x 0.9 = 0.585

Volume of fine aggregate content =1 – 0.585 =0.415

VIII MIX CALCULATIONS OF M50 GRADE CONCRETE

a) Volume of concrete = 1m3

b) Volume of cement = (Mass of Cement/ Its Specific Gravity ) X (1/1000)

= (410/3.12) X (1/1000)

= 0.131 m3

c) Volume of Water = (Mass of water/specific gravity of water) X (1/1000)

= (143/1) X (1/1000)

= 0.143 m3

d) Volume of Superplasticizer = (Mass of Superplasticizer / Specific gravity of admixture) X (1/1000)

= (8.2/1.145) X (1/1000)

= 0.007 m3

e) Volume of all aggregate = (a – (b + c + d))

= 1 – (0.131 + 0.143+0.007)

= 0.719 m3

e) Mass of coarse aggregate = Volume of All Aggregate X Volume of Coarse Aggregate X Specific Gravity of Coarse Aggregate X 1000

= 0.719 x 0.585 x 2.74 x 1000

= 1152.48 kg

f) Mass of fine aggregate = Volume of all aggregate X volume of fine aggregate X Specific gravity of fine aggregate X 1000

= 0.719 x 0.415 x 2.56 x 1000

= 763.86 kg

MATERIALS QUANTITY

Cement = 410 kg/m3

Water = 143 kg/m3

Super plasticizer = 7 kg/m3

Fine aggregates = 763.86 kg/m3

Coarse aggregate = 1152.48 kg/m3

To find the design mix ratio divide the calculated value of all materials by the weight of cement

Mix Ratio of M50 Grade concrete by weight is
Cement : F.A : C.A : Water=1 : 1.472 : 3.043 : 0.35