Challenge

Project - Data Handling and Interpolation

AAmitesh Yadav19 Oct 2022

Data Interpolation:- it is the method to find the new data point based on discrite known set of data point.

way of data interpolatin:-

(1) one dimension data interpolation:- let y=f(x) ; then we can find value of y for any value of x is known as one dimension data interpolatin (interp1) it is also known as linear interpolatin

ynew=interp1(x,y,xnew,method)

(2) two dimension data interpolatin:- let z=f(x,y) ; we find znew at any (x1,y1) is know as two dimension data interpolatin

znew=interp2(x,y,z,xnew,ynew,method)

three dimension interpolatin:-let v=f(x,y,z) ; we find vnew at any (x1,y1,z1) is known as three dimension interpolatin

vnew=interp3(x,y,z,v,xnew,ynew,znew,method)

spline interpolatin:-one dimension interpolatin that use cubic splines to find the values

clc

clear

close all

%reading data from excel

a=xlsread("VI (1).xlsx");

v=a(:,1);

i=a(:,2);

% interpolation linear

k=-17.3:0.1:0.9;

l=interp1(v,i,k);

% spline method m

m=interp1(v,i,k,'spline');

% computing current n for the given vv voltage data

vv=[-17.2 -13 -11 -9 -6 -1 0.11 0.25 0.5 0.61 0.66];

n=interp1(v,i,vv);

% ploted the v vs i

subplot(2,2,1);

plot(v,i,'o','LineWidth',2);

grid on

axis([-18 2 -30 5]);

xlabel('voltage v volt');

ylabel('current I ampare');

title('v vs i data')

% spline interpolation

subplot(2,2,3);

plot(v,i,'o',k,m,'g');

grid on

axis([-18 2 -30 5])

xlabel('voltage v volt');

ylabel('current i ampair');

title('v vs i splain interpolatin')

% liner interpolatin

subplot(2,2,2);

plot(v,i,'o',k,l,'g');

grid on

axis([-18 2 -30 5]);

xlabel('volatage v volt');

ylabel('current I ampair');

title('v vs i linear interpolation')

end

Project - Data Handling and Interpolation

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Ship work like this
in your own course.