Project 2
Ans-1
- The max heat generation of the battery
-> The maximum current in the drive cycle is -0.896 at 2 minutes(120 seconds)
-> Joule heat generated =I^2Rt=(-0.896^2)*0.5*120= 48.16 mili joule
The Max heat generated =Joule heat+Entropic heat
= 48.16 + 2( 48.16 )
= 144.48 mili joules
b) The SOC of the battery at 2 *104second of the battery operation.
Answer:-
Step1 -Prepared an excel sheet with time and current values given in question .
step -2 Import above excel sheet in Matlab.
Step3) Matlab Model.
Resistance=1 ohm.
Battery parameters :
Scope results:
Conclusion:-
In this project we have calculated the maximum heat. Also we have simulated the battery SOC, current and volatge for the given drive cycle. At 2 second, the battery SOC is around 99.3%.