Project 1 Mechanical design of battery pack

In here we are Going to Develop a battery pack Using

Cell: ANR26650M1-B and which are capable of producing 18KWH=18000WH

So for that first we will study about the architecture of the Li battery.

Cell Parameters:

Cycle Life Performance, 100% DOD, Various Temperatures and Discharge Rates of cell:

This are the characteristics of thiis cell,from this graph we have understood the process that is take place in the Li cell,now we need to go through the cell dimension and have to made the cell calculations.

Cell Dimensions

Cell calculation:

1) Volume of the cell:

so the formula is: Pi*r^2*h

From Datasheet of Cell, we have 'r' and 'h' values

r=0.0259696/2=0.013m

h=0.065m =

Volume of the cell = 3.14*(0.013^2)*0.065

=m3"> 0.0000344929m3m3

The volume of the cell is 0.0000344929m3">m3m3

From here we can able to find the total volume of the battery pack.

Cell Energy= Cell Capacity (Ah) × Cell Voltage (V)

= 2.5 × 3.3

= 8.25 Wh

Cell Energy is 8.25 Wh

The value of a single cell is used to calculate the total energy of the battery pack.

Single Cell Energy Density

Volumetric energy (Wh/m³) = Single Cell Energy / Volume of each cell

= 8.25 Wh / 0.0000344929m³

=2,39,179.6572 Wh/m³

Single Cell Energy Density= 2,39,179.6572 Wh/m³

Design Battery pack Using Series and parallel Connection.

There are 50 cell are in series and 44 cells are in parallel, and as above maintioned we are going to use Cell: ANR26650M1-B this cells.

Battery pack calculation:

Now we calculated parallel and series combinations so we can now calculate total no of cells required

Total no of cells: Series cells * parallel cells

:50*44

:2200.

Total no of cells required are 2200.

So from series and parallel combination, we can calculate the voltage of battery pack and the current of the battery pack.

Voltage= no of cell in series* nominal voltage.

= 50*3.3

= 165V

The total value of voltage is 165V.

Current=No of parallel cells * cell capacity

= 44*2.5

=110Ah.

The total value of Current is 110Ah

So now we can calculate the how much mount of energy this combination have by product of voltage and current, and check the it will satisfied or not our requirement

Energy= Voltage * Current

= 165 * 110

= 18150WAh

The total value of Energy is 18150WAh.

So we have done our calculations

now we have total no of cells and volume of single cell so we can calculate the total volume required for battery pack

Total volume = no of cells * Volume of single cell

= 2200 * 0.0000344929

=0.07588438m3">m3m3

Total volume required for battery pack is 0.07588438m3">m3m3

We also have single cell weight from that we can calculate the total weight of battery pack without other mechanical and electrical connections.

Weight = No of cells * weight of single cell.

= 2200 * 0.076

= 167.2kg

Weight of battery pack is 167.2kg

Energy dencity= volume * battery pack energy

= 0.07588438 * 18150

= 1,377.301497kWh/m^3

Energy dencity is 1,377.301497kWh/m^3

so by analysing all this calculations we can create a battery pack .

so we can conclude our battery with its specifications;

2112 cells will have 50S / 44P

1.Package: 50S / 44P

2.Capacity: 110 A

3.Voltage: 165

4.No of Cells: 210

5.Power: 18150Wh or 18.15 kWh

Now let me provide with a cell geomtry like battery holder (upper lower)and other battery holdings with some reference.

Joining ofCell Battery Pack

The suitability of joining methods to build battery packs using cylindrical cells is shown below: