Challenge

Project 1 - Creation of user defined data type to implement the user interfaces for working with ‘Set’ (Mathematical Set theory) using Linked List

Project 1 - Creation of user defined data type to implement the user interfaces for working with ‘Set’ (Mathematical Set theory) using Linked List

Solution:

/*

* Mathe_Sets.c

*

* Created on: Jul 26, 2023

* Author: MD.Ansar

*/

#include <stdio.h>

#include <stdlib.h>

// A structure of linked list node

struct node

{

int data;

struct node *next;

} *LLOne, *LLTwo, *unionLL, *intersectionLL;

void initialize()

{

LLOne = LLTwo = NULL;

}

//Given a Inserts a node in front of a singly linked list.

void insert(struct node **head, int num)

{

// Create a new Linked List node

struct node* newNode = (struct node*) malloc(sizeof(struct node));

newNode->data = num;

// Next pointer of new node will point to head node of linked list

newNode->next = *head;

//make new node as new head of linked list

*head = newNode;

}

// Searches an element in Linked List by linearly traversing from head to tail

int search(struct node *head, int num)

{

while (head != NULL)

{

if (head->data == num)

{

return 1;

}

head = head->next;

}

return 0;

}

//Returns the union of two given linked list

struct node* findunion(struct node *LLOne, struct node *LLTwo)

{

unionLL = NULL;

// Add all nodes of first Linked List to unionLL

struct node *temp = LLOne;

while(temp != NULL)

{

insert(&unionLL, temp->data);

temp = temp->next;

}

// Insert those nodes of LLTwo which is not present in LLOne

while(LLTwo != NULL)

{

if(!search(LLOne, LLTwo->data))

{

insert(&unionLL, LLTwo->data);

}

LLTwo = LLTwo->next;

}

return unionLL;

}

//Returns the Linked List which contains common nodes of two given linked list

struct node* intersection(struct node *LLOne, struct node *LLTwo)

{

intersectionLL = NULL;

//Search every element of LLOne in LLTwo, If found then add it to intersection List

while(LLOne != NULL)

{

if(search(LLTwo, LLOne->data))

{

insert(&intersectionLL, LLOne->data);

}

LLOne = LLOne->next;

}

return intersectionLL;

}

//Prints a linked list from head node till tail node

void printLinkedList(struct node *nodePtr)

{

while (nodePtr != NULL)

{

printf("%d", nodePtr->data);

nodePtr = nodePtr->next;

if(nodePtr != NULL)

printf("-->");

}

}

int main()

{

int i, LLOneCount, LLTwoCount, temp;

initialize();

//Creating First linked List

printf("Enter number of nodes in first Linked List\n");

scanf("%d", &LLOneCount);

printf("Enter %d integers\n", LLOneCount);

for(i=0; i<LLOneCount; i++)

{

scanf("%d", &temp);

insert(&LLOne, temp);

}

printLinkedList(LLOne);

printf("\nEnter number of nodes in second Linked List\n");

scanf("%d", &LLTwoCount);

printf("Enter %d integers\n", LLTwoCount);

for(i=0; i<LLTwoCount; i++)

{

scanf("%d", &temp);

insert(&LLTwo, temp);

}

printLinkedList(LLTwo);

//printing Union of two given linked list

findunion(LLOne, LLTwo);

intersection(LLOne, LLTwo);

printf("\nUnion Linked List\n");

printLinkedList(unionLL);

printf("\nIntersection Linked List\n");

printLinkedList(intersectionLL);

return 0;

}

Output:

8 9 7 5 6 3 2 4

8 6 9 7 4 2 3 1

Enter number of nodes in first Linked List

Enter 8 integers

8-->4-->2-->3-->6-->5-->7-->9

Enter number of nodes in second Linked List

Enter 6 integers

1-->3-->2-->4-->7-->9

Union Linked List

1-->9-->7-->5-->6-->3-->2-->4-->8

Intersection Linked List

9-->7-->3-->2-->4

Note:

Viav has done by Raju Mangalwede and he had told me to submit the project.

All the files had attached.

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