Project 1 - Creation of user defined data type to implement the user interfaces for working with ‘Set’ (Mathematical Set theory) using Linked List

Creation of user defined data type to implement the user interfaces for working with ‘Set’ (Mathematical Set theory) using Linked List

Answer:

/*
* pro.c
*

#include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
// Link list node
struct Node {
int data;
struct Node* next;
};
//function declaration
void push(struct Node** head_ref, int new_data);
int isPresent(struct Node* head, int data);
// Function to get union of two linked lists head1 and head2
struct Node* getUnion(struct Node* head1, struct Node* head2)
{
struct Node* result = NULL;
struct Node *t1 = head1, *t2 = head2;
// Insert all elements of list1 to the result list
while (t1 != NULL)
{
push(&result, t1->data);
t1 = t1->next;
}
// Insert those elements of list2 which are not present in result list
while (t2 != NULL)
{
if (!isPresent(result, t2->data))
{
push(&result, t2->data);
}
t2 = t2->next;
}
return result;
}
// Function to get intersection of two linked lists head1 and head2
struct Node* getIntersection(struct Node* head1, struct Node* head2)
{
struct Node* result = NULL;
struct Node* t1 = head1;
// Traverse list1 and search each element of it in list2. If the element is present in list 2, then insert the element to result
while (t1 != NULL)
{
if (isPresent(head2, t1->data))
{
push(&result, t1->data);
}
t1 = t1->next;
}
return result;
}
// A utility function to insert a node at the beginning of a linked list
void push(struct Node** head_ref, int new_data)
{
// allocate node
struct Node* new_node = (struct Node*)malloc(sizeof(struct Node));
// put in the data
new_node->data = new_data;
// link the old list off the new node
new_node->next = (*head_ref);
// move the head to point to the new node
(*head_ref) = new_node;
}
// function to print a linked list
void printList(struct Node* node)
{
while (node != NULL)
{
printf("%d ", node->data);
node = node->next;
}
}
// function that returns true if data is present in linked list else return false
int isPresent(struct Node* head, int data)
{
struct Node* t = head;
while (t != NULL)
{
if (t->data == data)
{
return 1;
}
t = t->next;
}
return 0;
}
// Driver program to test above function
int main()
{
int n,m,temp;
printf("enter the value of number of value in link list(both):-");
fflush(stdout);
scanf("%d %d", &n, &m);
// Starth structure pointer with the empty list
struct Node* head1 = NULL;
struct Node* head2 = NULL;
struct Node* intersecn = NULL;
struct Node* unin = NULL;
//for loop for link list1
for(int i=0;i<n;i++)
{
printf("Enter the value in link list1 %d:-",i);
fflush(stdout);
scanf("%d", &temp);
push(&head1, temp);
}
//for loop for link list2
for(int i=0;i<m;i++)
{
printf("Enter the value in link list2 %d:-",i);
fflush(stdout);
scanf("%d", &temp);
push(&head2, temp);

}
//call the function of intersection
intersecn = getIntersection(head1, head2);
//call the function of union
unin = getUnion(head1, head2);
printf("\n First list is ");
//function calling with structure pointer as argument
printList(head1);
printf("\n Second list is ");
printList(head2);
printf("\n Intersection list is ");
printList(intersecn);
printf("\n Union list is ");
printList(unin);
return 0;
}