Project 1
Aim:
To design the battery pack with the capacity 150Kw 120V by using 3500mAh 3.6V. And BMS topology for the battery pack
Calculations:
To design the battery pack we need cells which are connected in series and parallel to meet the requirment. The required condition - 120v and 150kW
Let us concider the cells with
Nominal voltage = 3.6v
Capacity = 3500mAh = 3.5Ah
To meet the requirment of 120v and 150Kw, we need to find the number of cells connected in series and parallel.
First convert the battery capacity 150Kw to Ah
Amper hour = Watt hour / Voltage
Amper hour = 150*1000 / 120 = 1,250 Ah
Series: In series connection the voltage multiplies. Hence to get the no of cells in series with nominal cell value of 3.6 v to meet 120v, we must do the following
Number of cells in series = required voltage / Nominal voltage of the cell
Number of cells in series = 120/3.6 = 33.33
We need to round off to lower value and higher value
Case-1) Number of cells in series = 33
Case-2) Number of cells in series = 34
Total volatge = nominal votage of cell * number of cells in series
| Number of cells in series | total nominal voltage | Requred voltage | |
| Case - 1 | 33 | 33*3.6 = 118.8 | 120 |
| Case - 2 | 34 | 34*3.6 = 122.4 | 120 |
The condition to choose the number of cells are
Nominal voltage of battery should not exceed the Load voltage (120v)
Max Voltage of battery should be less than the Load Max Voltage
Min Voltage of battery should be greater than the Load min Voltage
We have to round off to lower value so that it will not excide the required value
Therefore Number of cells in series = 33
Output total voltage will be 118.8V
The output voltage can be adjusted to 120v by a Buckboost converter to meet the requirment of 120v
Parallel:
Number of cells in parallel = required capacity / cell capacity
Number of cells in parallel = 1,250Ah / 3.5Ah = 357.14
We have to round off to lower value and higher value
Case-1) Round off to lower value = Number of cells in parallel = 357
Case-2) Round off to higher value Number of cells in parallel = 358
The output capacity = cell capacity * number of cells in parallel
| Number of cells in Parallel | total Capacity(Ah) | Required current | |
| Case - 1 | 357 | 357*3.5 = 1,249.5 | 1250 |
| Case - 2 | 358 | 358*3.5 = 1,253 | 1250 |
We can round off to higher value = 358
The output capacity = each cell capacity * number of cells in parallel = 358*3.5 = 1,253 Ah
The number of cells in Parallel = 357
The Output Capacity will be 1,253Ah
The Current can be limitted to requied value by using current limiters.
BMS topology:
Topology Adaption:
1. Since 18 cells are in connected in series
2. Large energy storage: 150kW but less than 1Mega Watt
considering above scenario, we adopt Master slave topology with following configuration
1. cell pack 1= 17 cells in series
2. cell pack 2= 17 cells in series
