Front View Geometry and Roll Center Height 1

Co-ordinates are as below:

y_1=105;
z_1 = 425;
y_2 = 285;
z_2= 460;

y_3= 105;
z_3=185;
y_4=370;
z_4=170;

o_ytyre=0;
o_ztyre=0;

%%Slope for Line 1 and Line 2 as below:

m_line1=(z_2-z_1)/(y_2-y_1);
m_line2=(z_4-z_3)/(y_4-y_3);

%%Line equations are as below :

z_line1 = m_1*(y-y_1)+ z_1;
z_line2 = m_2*(y-y_3)+ z_3;

%% Line equations obtained are as below:

z_line1 = 0.1944(y-105)+425

z_line2 = -0.0566(y-105)+185

%%equating these line equatios to find out the intersection point (IC) co-ordinates

z_line1 = z_line2

0.1944(y-105)+425 = -0.0566(y-105)+185

y = -850.992

z = 239.113

%%Hence, Instantaneous centre co-ordinates are (y,z) = (-850.992,239.113)

%%Similarly, slope of the line connecting IC and Tire center on ground = m3= -0.281

%%The intersection point (RCH) between the center line of vehicle at y_c = 800 and the line connecting IC and Tire center on ground is obtained by equating these line equations as below:

m3*y= 800

z_c = -224.785

The Roll centre height is -224.785mm (below the ground)

I will try to make the MATLAB program that can find out these parameters.