Challenge

Foundation Design using SAFE

1.ANS:-

  • Open SAFE software
  • Create a new model
  • Edit the settings

  • Edit the structural geometries and properties as per the previous problem which is given below:-

Size of column = 400 mm * 400 mm

Unfactored gravity load (DL+LL) = 2000 KN

Safe bearing capacity of soil = 150 KN/m^2

Assume M25 grade concrete and Fe 500 HYSD bars

Settlement = 50 mm

Take FOS = 3

Sub- grade modulus = FOS* Safe bearing capacity/settlement = 150*3/0.05 = 9000 KN/m^3

Unfactored gravity load = 2000/1.5 = 1333.33 KN

Dead load = 1333.33/2 = 666.6 KN

Live load = 1333.33/2 = 666.6 KN

Yield strength of steel , fy = 500 N/mm^2

Ultimate strength of steel, fu = 575 N/mm^2

Area of footing = 1333.33/150 = 8.88 m^2

Size of footing = L = B = √(8.88) = 3 m

Adopt 4 m * 4 m for square footing

  • Define materials

  • Add new material property for M25 concrete

  • Add new material property for Fe 500 HYSD bar

  • Define slab property data

  • Assign the area spring property

  • Assign the load assignment force

  • Define load combinations

  • Check the model

  • Run the analysis

Here the displacement for both dead and live load is within the limit

  • Check for bearing pressure under serviceable limit stage

Here the maximum soil bearing pressure is 84 KN/m^2 within the permissible limit i.e. 150 KN/m^2

  • Again unlock the model
  • Create design strip for design footing

  • Again run the analysis
  • Check the flexural reinforcement

Here the maximum reinforcement is 1269.58 mm^2 per metre

  • Check for punching shear

Punching shear is 0.792 N/mm^2 which is less than 1. Hence it is safe.

2.ANS:-

Size of column = 600*600

Unfactored gravity load (DL+LL) = 1175 KN

Length of pile = 16 m

Diameter of pile = 500 mm

Load carrying capacity = 200 KN

Assume M25 grade of concrete and Fe 500

No of piles = 1175/200 = 6

Modulus of Elasticity, E = 5000*√(fck) = 5000*√(25) = 5000*5 = 25000 N/mm^2

Area of piles, A= 3.14/4*500^2 = 193649.54 mm^2

Spring constant, k = E*A/L = 25000*193649.54/16000 = 306796.15 N/mm = 306796.15 KN/m

Spacing of piles = 2.5*500 = 1250 mm with 150 mm projections on either side

Length of pile cap = 1250+1250+(250+150)*2 = 3.3 m

Width of pile cap = 1250+2*400 = 2.05 m

Thickness of pile cap = 2*Diameter of pile + 100 = 1.1 m

  • Open SAFE software
  • Create new model template

  • Define material property

  • Define slab property type

  • Draw by points

  • Drag it to the four points for creating pile cap

  • Draw the points for creating pile caps at specified offset distance

  • Draw the column at mid point for specified offset distance

  • Draw the circular object and rectangular object for specified points which are been defined

  • Assign the joint springs for pile caps

  • Assign the spring constant value for Z azis is 30796.15 KN/m which has been calculated earlier i.e. k

  • Assign the joint assignment force for column both dead load and live load

  • Define load combinations

  • Check the design concrete slab preferences as per IS code 456-2000

  • Check the automatic mesh options

  • Check the model and run the analysis

Here the maximum deflection comes to around 4 mm which is safe

  • Check for reaction

Here the reaction comes it around 288 KN

  • Untick the model and create the design strips

  • Click the model and check its design for both column strip

  • Run the analysis
  • Check its flexural reinforcememt

  • Check for punching shear

Hence it is safe within its permissible limit

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