Challenge

Week 7-Long Piston With Cam

OBJECTIVE :

To find out directional deformation ,equivalent stress and equivalent strain in given model

PROCEDURE :

Open the ANSYS WORKBENCH R2
select transient structural analysis
select engineering data and choose structual steel from general material list
import geomtry
rename its part
select structural steel as material for all parts
in contact section ,select both contact and flip the contact and target
select target and contact scopes properly
insert the body ground fixed joint ,select barrel follwer outer cylinder as its scope
insert body ground revelute joint and choose barrel shaft as its scope
insert body ground transilational joint and choose cam follower as its scope
select both joint contact in connection and change type to friction less for first cse and for the second and third cases choose frictional and input frictional coefficient as .1 and .2 respectivly
insert sizing in mesh section and select cam and groove which cam sliding in it as aits scope ,input element size as 3 mm
In analysis section input number of step as 9
select for the first step keep large deflection on weak spring as program controlled
in non linear controls select stabilisation as constant input value as .1,keep ON activation for first substep
in output controls keep no for contact miscellaneous others keep as yes
insert joint load in transient settings select joint revolute -groundto barrel ,choose type as rotation input data by tabular data
insert direcional deformation equivalent stress and equivalent strain in solution section
run slove

RESULT :-

CASE I :-

FRICTION LESS CONTACT :-

1 . DIRECTIONAL DEFORMATION :-

2. EQUIVALENT STRESS :-

3. EQUIVALENT STRAIN :-

CASE II :-

FRICTIONAL CONTACT (COEFFICIENT OF FRICTION IS .1)

1 . DIRECTIONAL DEFORMATION :-

2. EQUIVALENT STRESS :-

3. EQUIVALENT STRAIN :-

CASE III :-

FRICTIONAL CONTACT (COEFFICIENT OF FRICTION IS .2)

1 . DIRECTIONAL DEFORMATION :-

2. EQUIVALENT STRESS :-

3. EQUIVALENT STRAIN :-

TABULATION :-

CONTACT TYPE	DIRECTIONAL DEFOMATION (mm)	EQUIVALENT STRESS (MPa)	EQUIVALENT STRAIN (mm/mm)
FRICTIONLESS	20.324	1682.9	0.0084626
FRICTIONAL(COEFFICIENT OF FRICTION IS .1)	20.342	2133.4	0.010727
FRICTIONAL (COEFFICIENT OF FRICTION IS .2)	20.359	2660.5	0.013381

CONCLUSIONS :-

Directional deformation is more infrictional contact which coefficient of friction is .2
equivalent stress is high as 2660.5 MPa in frictional contact which coefficient of friction is .2 and equivalent strain is maximum shown in frictional contact of coefficient of .1 and it is 0.013381
equivalent strain and directional deformation is minimum among three cases is fricionless contact and is 0.0084626 and 20.324 mm respectivly

INFERENCE :-

Directional deforamtion and equivalent stress are mximum shown in frictional contact due to frictional effect its causes more stress developement and it leads to deform more than that of same model with frictionless contact

Ship work like this
in your own course.