Week 3 Challenge
1.1
- DEAD LOAD
- LIVE LOAD
- WIND LOAD
- EARTHQUAKE LOAD
1.2
- THE RATIO OF LONGER SPAN AND SHORTER SPAN IS GREATER THAN 2 IS CALLED ONE WAY SLAB
- WHERE Ly/Lx >2.
- WHERE LOAD ACTING ON TWO DIRECTION IN A SLAB IS CALLED ONE WAY SLAB.
1.3
- UNIT WEIGHT OF STRUCTURAL STELL IS 7840 Kg/m3
- UNIT WEIGHT OF SOIL IS 18 KN/m3
1.4
- CIRCULAR
- RECTANGLE
- TEE
- TRAPEZODIAL
- GENERAL
1.5
- PRIMARY BEAM MEANS RADIATION WHICH PASESS THROUGH AN APERTURE OF THE SOURCE HOUSING BY A DIRECT PATH FROM THE X-RAY TUBE OR A RADIOACTIVE SOURCE LOCATED IN THE RADIATION SOURCE HOUSING.
2.1
- K1 = PROBABILITY FACTOR
- K2 = TERRAIN,HEIGHT AND STRUCTURE SIZE
- K3 = TOPOGRHAPY FACTOR
- DESIGN WIND PRESSURE :- THE DESIGN OF WIND PRESSURE AT ANY HEIGHT ABOVE MEAN GROUND LEVEL SHALL BE OBTAINED BY THE FOLLOWING RELATIONSHIP BETWEEN WIND PRESSURE AND WIND VELOCITY.
- Pz = 0.6Vz2
2.2
- SLAB
- SECONDARY BEAM
- PRIMARY BEAM
- COLUMN
- FOUNDATION
3.1
ONE WAY SLAB
- THE RATIO OF LONGER SPAN AND SHORTER SPAN IS GREATER THAN 2 IS CALLED ONE WAY SLAB
- WHERE Ly/Lx >2.
- WHERE LOAD ACTING ON TWO DIRECTION IN A SLAB IS CALLED ONE WAY SLAB.
TWO WAY SLAB
- THE RATIO OF LONGER SPAN AND SHORTER SPAN IS LESS THAN OREQUAL TO 2 IS CALLED TWO WAY SLAB
- WHERE Ly/Lx <
- WHERE LOAD ACTING ON FOUR DIRECTION IN A SLAB IS CALLED TWO WAY SLAB.
3.2
- THE SECOND BEAMS ARE PRIMARLY CONNECTED TO THE PRIMARY BEAMS MAINLY SIMPLY SUPPORTED BEAMS.
- THE SECONDARY BEAMS ARE PROVIDED FO THE BETTER DISTRIBUTION OF SLAB LOADS ALONG WITH PRIMARY BEAMS WHICH RESETS ON THEN SLABS.
- MAINLY SECONDARY BVEAMS ARE CONNECTED WITH PRIMARY BEAMS AND THAT PRIMARY BEAMS ARE DIRECTLY CONNECTED WITH COLUMNS.
- IN SECONDARY BEAMS IMPORTANT TO RELEASE THE END MOMENT AT THE SUPPORTS,BECAUSE OF THIS ALL THE SECONDARY BEAMS ARE PROVIDED WITH THE PINNED CONNECTION.

3.3
a.
- DEAD LOAD : IS 875 PART 1
- LIVE LOAD : IS 875 PART 2
- WIND LOAD : IS 875 PART 3
- SEISMIC LOAD : 13927
b.
- DEAD LOAD DEPENDS UPON UNIT WEIGHT.
- VOLUME OF RECTANGULAR/CIRCULAR SECTION.
- LIVE LOAD DEPENDS UPON BUILDING TYPE.
- AREA OF TYPE OF ROOM.
c.
- A LOAD IS A COMBINATION OF DIFFERENT TYPES OF LOADS WITH SAFETY FACTORS APPLIED TO THEM.
- A STRUCTURE IS CHECKED FOR STRENGTH AND SERVICEABILITY AGAINST ALL THE LOAD CASES IT IS LIKELY TO EXPERIENCE DURING ITS LIFETIME.
3.4
PROPERTIES
- FOR ASSIGNING THE PROPERTIES GO TO THE PROPERTIES IN THAT A OPTION CALLED DEFINE.

- BY CLICKING THAT THE DAILOUGE BOX WILL BE OPENED LIKE THIS.

- IN THAT WE HAVE TO CHOOSE TYPE OF PROPERTY AND ASSIGNED IT TO MODEL.
SUPPORTS
- FOR ASSIGNING THE SUPPORTS GO TO THE SUPPORTS IN THAT CREATE OPTION IS THERE.

- BY CLICKING THAT OPTION THIS DAILOUGE BOX WILL APPEARS.

- AFTER THAT WE CAN CHOOSE THE TYPE OF SUPPORT ANS ASSIGNED IT TO THE MODEL.
3.5
- USING NODES CREATE A MODEL IN THE STTAD.PRO SOFTWARE

- SELECT ANY ONE BEAM FROM THE MODEL.
- GO TO THE INSERT NODE OPTION BY SELECTING THAT A DAILOUGE BOX WILL APPEARS LIKE THIS

- IN THE SELECT THE ADD MIDPOINT OPTION IT WILL ADDED AUTOMATICALLY.

- PRESS OK THE NODE WILL BE CREATED.

- DO IT AGAIN FOR THE OPPOSITE BEAM ALSO.
- THEN USING ADD BEAM OPTION ADD THE TWO NODES WHICH WE CREATE PREVIOUSLY THE SECONDARY BEAM IS CREATED LIKE THIS.

PRACTICAL
1
AIM:- CALCULATE THE WIND PRESSURE FOR THE GIVING BUILDING.
GIVEN DATA:-
BUILDING DIMENSION : 20M X 30M X 20M HEIGHT RCC.
BUILDING USAGE : HOSPITAL BLOCK IN CITY CENTRE
LOCATION : DARJEELING.
PROCEDURE :-
- FIRST WE CALCULATE THE DESIGN WIND SPEED(Vz).
- WE KNOW THE FORMULA.
- Vz = Vb x K1 X K2 X K3 X K4
WHERE
- Vb = BASIC WIND SPEED = 47 m/sec
- K1 = RISK CO-EFFICIENT = 1.07
- K2 = TERRAIN ROUGHNESS AND HEIGHT FACTOR = 0.8
- K3 = TOPOGRAPHY FACTOR = 1
- K4 = IMPORTANTANCE FACTOR = 1
THESE VALUES ARE WE CAN TAKEN FROM THE IS CODE 875:2015
- CALCULATION OF WIND PRESSURE:-
Vz = Vb X K1 X K2 X K3 X K4
= 47X1.07X0.8X1X1
= 40.23 m/sec
- NOW WE CAN CALCULATE THE WIND PRESSURE (Pz)
- WE KNOW THE FORMULA
Pz = 0.6 X Vz2
= 0.6 x (40.23)2
= 971.071

RESULTS:-
WIND PRESSURE IS CALCULATED.
2
AIM:- TO CALCULATE THE DEAD LOAD AND LIVE LOAD FOR THE ABOVE BUILDING WITH REFERENCE TO IS STANDARDS (ASSUME SUITABLE SECTIONS)
PROCEDURE:-
DEAD LOAD:-
DEAD LOAD DUES TO THE SLABS
- ASSUMING 150mm AS THICKNESS OF SLAB
- DEAD LOAD DUE TO ONE SLAB = LXBXHXT = 20X30X25X0.15 = 225KN
- TOTAL DEAD LOAD DUE TO ALL SLABS = NO.OF.SLABS X DEAD LOAD DUE TO ONE SLAB.
- NOW WE HAVE 5 SLABS = 5 X 225 = 1125 KN
DEAD LOAD DUE TO THE BEAMS
- CONSIDERING THE BEAM C/S 300mm X 400mm
- DEAD LOAD DUE TO BEAMS = 0.3X0.4X25 = 3 KN/m
LIVE LOAD :-
- WE CAN CALCULATE THE LIVE LOAD OF A GIVEN STRUCTURE BY USING THE IS 875:2015 PART-2 WHICH STAES THE DIFFERENT LIVE LOAD VALUES FOR DIFFERENT ROOMS.
- AS OUR BUILDING IS THE HOSPITAL BUILDING ALL THE PROPOSED LIVE LOAD VALUES FOR HOSPITA,L BUILDING ACCORDING TO THE IS 878:2015 PART-3 HAS BEEN LISTED BELOW
|
S.NO |
OCCUPANCY |
LIVE LOAD |
|
1 |
WARD ROOM,DORMITIORIES |
2.0KNm2 |
|
2 |
LABORATORY |
3.0KNm2 |
|
3 |
CAFETERIA |
3.0KNm2 |
|
4 |
TOILETS & BATHROOMS |
2.0KNm2 |
|
5 |
X-RAY ROOMS & OPERATING ROOMS |
3.0KNm2 |
|
6 |
OFFICE & OPD ROOM |
2.5KNm2 |
|
7 |
CORRIDOR & PASSAGES |
4.0KNm2 |
RESULTS:-
ALL DEAD LOADS AND LIVE LOADS ARE SHOWNED.