Week 10 Bullet penetrating a Bucket Challenge
Objective -to simulate a bullet penetrating into a bucket. You will need to use 3 different non linear materials for the bucket and analyse their behaviour for the same velocity of bullet. Apply the conditions for bullet as mentioned in the video itself. Attach an animation to show the behaviour in the three cases.
Solution -
We open the ansys workbench and add the three materials mentioned in the objective.
Materials properties
Stainless steel NL
Aluminium Alloy NL
Titanium alloy NL
The above three materials are used for the for the bucket
while for the bullet we use tantalum as the material.
Now we upload the model to the geometry and open it in space clam and see if there are any discontinuities in the model.
Update the model to the mechanical module. And Opening the module.
For the Explicit dynamic analysis we are not intrested in the contacts so we delete the contacts.
Now for the mesh we add the edge sizing and give a element size of 6 mm. As the bullet is going to pass through this edge, so we refin the mesh to get accurate results.
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Mesh for the spring joint is 3 mm element size.
Analysis Settings for are
maximum energy error is set to 5 and end time is set to 1e-2.
We give a velocity to the bullet of -1.39e5.
After setting up the problem we insert the required results to the solution. In this case we add equivalent stress and total deformation.
Case 1 - Stainless steel NL
Equivalent stress
Total Deformation
Case 2 - Aluminium alloy NL
Equivalent stress
Total Deformation
Case 3 - Titanium alloy NL
Equivalent stress
Total Deformation
Simulation Link
Aluminium Alloy NL
Stainless Steel NL
https://youtu.be/nKJMfi7JaUI
Titanium Alloy NL
https://youtu.be/T_SvtoNQah4
Comparison table
| parameters | Units | Case 1 (Aluminium Alloy NL) | case 2 stainless steel NL | case 3 titanium alloy NL | |
| 1 | Equivalent stress(max) | Mpa | 1061.2 | 1509.9 | 3463.9 |
| 2 | Total Deformation(max) | MM | 1390 | 1390 | 486.5 |
Conclusion-
Form the table we can say that the stress is maximum and deformation is minimum in Titanium alloy NL.
Total deformation is same for the aluminium alloy NL and stainless steel NL.
If we compare the stress for case 1 and 2 then Aluminium alloy NL has less stress as compare to Stainless steel NL.
Titanium provides maximum resisting force to the bullet so total deformation is less.