Challenge

Week 1 Understanding Different Battery Chemistry

SR.NO TYPES OF BATTERY MATERIAL USED CHEMICAL REACTION AT CATHODE AND ANODE
1 LCO

ANODE(LiC6)LITHIUM COBALT OXIDES

CATHODE(LiCoO2)GRAPHITE

DURING DISCHARGE

AT THE ANODE, THE LITHIUM-ION IS OXIDISED. LITHIUM IONS ARE RELEASED FROM THE CARBON ALONG WITH ELECTRONS

LiC6 = xLi^(+) + xe^(-) + C6

AT THE CATHODE LITHIUM IONS ARE ABSORBED BY LITHIUM DIOXIDE AND THE ELECTRODE IS REDUCED AND ALSO RECEIVES THE ELECTRONS FROM THE CIRCUIT

Li(1-x)CoO2 + xLi^(+) + xe^(-) = LiCoO2

hence

C6 + LiCoO2 = Li(x)C6+Li(1-x)CoO2

2 LMO

CATHODE(LiMn2O4)LITHIUM MANGANESE OXIDES

ANODE(LiC6)LITHIUM COBALT

AT THE ANODE THE LITHIUM ION IS OXIDISED. LITHIUM IONS ARE RELEASED FROM THE CARBON ALONG WITH ELECTRONS

LiC6 = xLi^(+) + xe^(-) + C6

Li(y) - xMnO4 + xLi^(+) + xe^(-) = Li(y)MN2O4

HENCE

Li(x)C6 + Li(y) - (x)Mn2O4 = LiC6 + Li(y)Mn2O4

3 NCA ANODE(LiC6) LITHIUM COBALT (LiNiMnCoO2)LITHIUM NICKEL MANGANESE COBALT OXIDE

AT THE ANODE THE LITHIUM ION IS OXIDISED. LITHIUM IONS ARE RELEASED FROM THE CARBON ALONG WITH ELECTRONS

LixC6 = LiC6 + xLi^(+) + xe^(-)

Liy−nx(NiaCobAlc)O2 + xLi^(+) + xe^(−) = Liy(NiaCobAlc)O2

LixC6+ Liy-x(NiaCobAlc)O2 = LiC6+ Liy(NiaCobAlc)O2

4 NMC

ANODE(LiC6) LITHIUM COBALT

CATHODE(LiNiMnCoO2) LITHIUM NICKEL MANGENESE COBALT OXIDE

AT THE ANODE THE LITHIUM ION IS OXIDISED. LITHIUM IONS ARE RELEASED FROM THE CARBON ALONG WITH ELECTRONS

LixC6 = LiC6+ xLi^(+) + xe^(−)

Liy−x(NiaMnbCoc)O2+ xLi^(+)+ xe^(−) = Liy(NiaMnbCoc)O2

LixC6+ Liy−xMn2O4 = LiC6+ LiyMn2O4

5 LFP

ANODE(LiC6) LITHIUM COBALT

CATHODE(LiFePO4)LITHIUM IRON PHOSPHATE OXIDES

AT THE ANODE THE LITHIUM ION IS OXIDISED. LITHIUM IONS ARE RELEASED FROM THE CARBON ALONG WITH ELECTRONS

LixC6 = LiC6+ xLi^(+) + xe^(−)

Liy−xFePO4+ nLi^(+)+ ne^(−) = LiyFePO4

LixC6+ Liy − xFePO4 = LiC6+ LiyFePO4

6 LTO

ANODE(Li2TiO3)LITHIUM TITANATE OXIDE

CATHODE(LiMn2O4)LITHIUM MANGANESE OXIDES

OR

CATHODE(LiNiMnCoO2) LITHIUM NICKEL MANGENESE COBALT OXIDE

AT CATHODE

4Mn2PO4+4Li^(+) + 4e^(-) = 4LiMn2O4

AT ANODE

Li4Ti5O12 + 4Li^(+) + 4e^(-) = 4LiMn2O4

HENCE

4Mn2O4 + Li4Ti5O12 = 4LiMn2O4 + Ti4O12

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