Challenge

Week 1 Stress Concentration on a Plate with hole

  • Compare the deformation and maximum stress developed on a structural steel model for the 2 cases :

CASE A

  • Model :

Element Size : 5 mm

Mesh Type : Tetrahedron

  • Boundary Condition :

A: Fixed Support

B: Load of 500N

  • Solution :

1) Equivalent Von Mises:

Max. Stress : 0.60154 MPa

2) Total Deformation :

Total Deformation : 0.00027479 mm Max.

CASE B

  • Model :

Element Size : 5 mm

Mesh Type : Tetrahedron

  • Boundary Condition :

A: Load of 500N

B: Fixed Support

  • Solution :

1) Equivalent Von Mises:

Max. Stress : 0.58646 MPa

2) Total Deformation :

Total Deformation : 0.00029701 mm Max.

CONCLUSION :

Stress is more in Case A while Total Deformation is more in Case B .

Case A - Stress : 0.60154 MPa Total Deformation : 0.00027479 mm

Case B - Stress : 0.58646 MPa Total Deformation : 0.00029701 mm

  • From an analysis standpoint, which of the design will you select? Explain why?

Explaination : From Design point of view , I will select Case B (With Multiple Holes) as the stress is less .

  • From a manufacturing standpoint, which of the design will you select? Explain why?

Explaination : From Manufacturing point of view , I will Select Case A as total deformation is less and it will be manufactured less operation and development time will also be less which will increase the production.

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