Challenge

To calculate wind load for industrial steel structures and to apply it by using TSD

  1. Generate manual wind loading in the design report based IS code as per the following input
  • Basic wind speed = 39m/s
  • Terrain category 2

Ans:-

Terrain category is given as 2

Vb = Basic wind speed which is given as 39m/s

Normally basic wind speed is selected from appendix A of code book IS 875 (Part-III) which is given based on wind speed in various cities

Design wind speed Vz= Vb*K1*K2*K3*K4

Where Vz depends on risk level, terrain roughness, height, size of structure, local topography

K1 = Probability factor

It is taken from table 1 of IS 875 III

Life of structure is taken as 50 yrs and wind speed is given as 39m/s. Based on this K1 =1

K2 = Terrain, height, structure factor which is taken from table 2 = 1.05

K3 = Topography factor which is taken as 1 (θ">θθ<3 = 1 and θ">θθ>3 = 1 to 1.36)

K4 = Importane factor for cyclonic region K4 is taken as 1.15

Where K4 = 1.3 Structure for post cyclonic importance
= 1.15 Industrial structure
= 1 All other structure

  • Wind speed = 39m/s
  • Life period = 50yrs
  • Terrain category = 2
  • Design wind speed Vz = Vb x K1 x K2 x K3 x K4 = 39 x 1 x 1.05 x 1 x 1.15 = 47.09m/s
  • Design wind pressure = Pz = 0.6 x Vz^2">^2 = 1330N/m2 = 1.33KN/m2
  • Length = 18m, Width = 18m, Height = 16.88m
  • L/W = 1 and H/W = 0.937
  • External pressure coefficients for wall is taken from table 5 IS 875 III (H/W=0.937)

  • Roof angle is calculated and based on roof angle external pressure for roof is calculated based on table of IS 875 III
  • We have calculated roof angle as 20 degree.

Calculations from data:-

  1. Based on the above calculation apply the loadings on the model

Application of wind load on Model

For wall section

For Roof section

  1. On a separate model generate wind loading using wind wizard.

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