Challenge

Section Modulus calculation and optimization

SECTION MODULUS OF HOOD

AIM :-

Section modulus calculation and optimization.

OBJECTIVE:-

Use section of the hood and calculate the section modulus.

INTRODUCATION:-

Section modulus is a gemoetric propertry of the given cross section desgin of beam.this properties is used to desgin the include area for tension and shear.the radius of gyration, cpmpression and moment of interia,polar moment of interia.the realtion between these properties is highly depends upons the shape of figure.the section modulus can also found as numerical values for common profiles in tables.it used to calculate the strength of the beam or column.

S=I/Y

Here,

S = Section modulus

I= Moment of Inertia (Unit mm 4)

Y= Distance from Neutral axis to the extreme end (unit mm)

The Unit of a (“section modulus” )is (mm3)

TYPES OF SECTION MODULUS :-

1-ELASTIC SECTION MODULUS.

2-PLASTIC SECTION MODULUS.

CALCULATION :-

CASE 1=(BEFORE OPTIMIZATION)

STUDY- The hood which was already created is imported and the section of area analysis is done..

MOI (max) = 8.928754301e+07 (mm^4)

MOI (min) = 3.196609661e+05 (mm^4)

As per the section modulus equation,

S = I/Y

I = MOI (min) value is considered

Y = Total distance /2, Total distance =875.5680mm

Y = 875.5680 / 2

= 437.784 mm

Therefore, S = 319660.966 mm^4/437.784 mm

S = 730.179 mm^3

CASE 2=(AFTER OPTIMIZATION)

STUDY- The hood inner pannel 's has curve offset 0.5 , outwards and section inertia analysis is done same , as case 1 have a closed curve.

MOI (max) = 8.910657812e^07 mm^4

MOI(min) = 3.264954768e^05 mm^4

As per section modulus equation,

S = I / Y

I = MOI (min) value is considered

Y = Total distance /2, Total distance =875.5680mm

Y = 875.5680 / 2

= 437.784 mm

Therefore, S = 326495.4768 mm^4 / 437.784 mm

S = 745.792 mm^3

CONCULSION :-

The section modules optimization reveals that hood panel provide better (MOI) moment of inertia .It can be improved by increasing the area ofMOI of given section which we can study in case 1 and in case 2....

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