Section Modulus calculation and optimization

Step 1: Calculate the Section Modulus of the Original Design

Assume the following values for the original section:

• Moment of Inertia, $I$I: 1000 cm$^4$4
• Distance to the neutral axis, $y$y: 20 cm

S :- S=yI​=20cm1000cm4​=50cm3 ; -----(1)

new Moment of Inertia, $I$I: 3000 cm$^4$4 (increased due to shape and material distribution)

New distance to the neutral axis, $y$y: 30 cm

S;- Snew​=yI​=30cm3000cm4​=100cm3 ;------(2)

• Original Section Modulus, $S$S: 50 cm$^3$3 ;- (1)
• New Section Modulus, $S_{new}$Snew​: 100 cm$^3$3; (2)

Answers:

The new design features a Section Modulus of 100 cm$^3$3, which is an improvement over the original design's 50 cm$^3$3.