Challenge

Section Modulus calculation and optimization

Section Modulus:

  • The section modulus (S) is geometry property of the cross section used for designing beams and flexural members. It does not represent anything physically.

Case 1: Before Optimization

The hood which was already created is imported and the section inertia analysis is done.

We have to make sure that the curve obtained is a single/closed curve.

I (MAX) = 8.838734721e+07 (mm^4)

I (MIN) = 2.467600180e+05 (mm^4)

As per the section modulus equation,

S = I/Y

I = MOI (min) Value is considered

Y = Total distance / 2, Total distance = 875.7184 mm

Y = 875.7184 / 2

= 437.859 mm

Therefore, S = 246760.018 mm^4 /437.784 mm

S = 563.560 mm^3

Case 2: After Optimization

The hood inner panel’s curve is offset by 0.5mm outwards and section inertia analysis is done same as case 1 for a closed curve.

I (MAX) = 8.844363726e+07 (mm^4)

I (MIN) = 2.523813326e+05 (mm^4)

As per the section modulus equation,

S = I/Y

I = MOI (min) Value is considered

Y = Total distance / 2, Total distance = 875.7184 mm

Y = 875.7184 / 2

= 437.859 mm

Therefore, S = 252381.332 mm^4 / 437.859 mm

S = 576.398 mm^3

Conclusion:

Resulting by comparing case 1 & case 2,

  1. The section modulus value of case 2 is higher than the case 1
  2. As we increase the section area, the moment of inertia & section modulus increase which means strength and load material also increase. Which the moment of inertia directly proportional to the strength of the material.
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