Challenge

Section Modulus calculation and optimization

I (MAX) =9.019686476e+07(mm^4)

1 (MIN) = 2.954825767e+05 (mm^4)

Y = 880.4334

As per the section modulus equation,

S=I/Y

I = MOI (min) Value is considered

Y = Total distance / 2

Y=880.4334/2

Y=440.2167

=2.9S4825767x10^4

=29548.25767/440.2167

=67.12207344

=67.12 MM^3

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