Section Modulus calculation and optimization
SECTION MODULUS OF THE HOOD
It is the ratio of area moment of inertia about the neutral axis and to the distance of outermost fiber from the neutral axis.
S= I/Y
Where as;
S = Section of modulus,
I = Area moment of inertia,
Y = Distance from neutral axis to the outermost fiber.
CALCULATION;
- Before optimization :
MOI (max) = 9.015658660e + 07(mm^4) MIN (min) = 2.859547026e + 05(mm^4) y = 876.8033/2 = 438.40165 mm. S = I/Y (2.859547026*10^3+05) / 438.40165 = 6.5340mm^3 - After optimization :
MOI (max) = 8.998955964e + 07(mm^4) MIN (min) = 2.900688976e + 05(mm^4) y = 438.40165 S = I/Y (2.900688976*10^3 + 05) / 438.40165 = 6.6279 mm^3