Section Modulus calculation and optimization

SECTION INERTIA:

CASE 1:

I (MAX):8.97749e+07mm^4

I (MIN):2.9871e+mm^4

As per the section modulus equation,

S = I/Y

Y = Total distance / 2

Y=363.3/2

y=189.65

s=8977497mm^3/189.65mm

s=47,337.1mm^3