Reinforcement Detailing of Beams from ETABS output

Aim

      To create G+4 building and thento run the analysis in the ETABS 

Detailing rule of any reinforcement concrete member :

     1 Minimum reinforcement for shrinkage & temperature 

     2 Reinforcement required for limiting crack - width 

     3 Ultimate limit state design rebar requirement 

     4 Ductility rebar requirement 

  Among these Four Whichever is greater should be drawn in RC beam detailing 

 Minimum longitudinal reinforcement as per IS -13920 -2016 clause 6.2.1 As = 360 mm^2 

 Minimum shear/transverse reinforcement as per IS - 456 -2000 clause 26.5.1.6 (Assuming 1000 mm spacing in the formula ) Asv = 332 mm^2 

 Development length as per IS-456-2000 clause 26.2.1 Ld = 41 * diameter of bar 

Procedure 

         To create the G+4 building and then to run the analysis for that open the document file in the ETABS and then by using the analyse we can analyse the structure 

        And then by using the concrete frame design command we can run the structure thus the longitudinal reinforcement details are shown in the structure

   To check the shear reinforcement in ths structure 

           Click the concrete frame design - Display design info - Shear reinforcing - ok thus the sher reinforcemet details are loaded in the structure 

Shear reinforcement of Beam at Grid - 3 from ETABS (cm2/1000 mm )

Longitudinal reinforecement of Beam t grid - 3 from ETABS (mm2)

Additional reinforcement guideline from IS -13920 - 2016 (Clause 6)

As per IS -13920-2016 clause 6.3.3 (b)                                   Mas = 174 kNm 

     Sway shear force right                                                       Mbh = 293 kNm          Vu,a = 46 kN 

     Vu,a = Vu,a^D+L -1.4 Mu^As + Mu^Bh /LAB and                Lab = 4.725 m           Vu,b = 230 kN 

       Vu,b = Vu,b^D+L +1.4 Mu^As + Mu^Bh /LAB                    Vd+l = 92 kN 

 Sway shear force left                                                              Mah= 234 kNm 

     Vu,a = Vu,a^D+L -1.4 Mu^Ah + Mu^Bs /LAB and                Mbs = 155 kNm       Vu,s = 185 kN 

       Vu,b = Vu,b^D+L +1.4 Mu^As + Mu^Bs /LAB                   Lab = 4.725 m         Vu,b = 45 kN 

                                                                                             Vd+l = 70 kN

To calculate the sway shear we have to create the load combination 

     Dead load 

     Live load 

     Brick wall 

     Floor finishes  

Enter the specific value for the given loads and then check the shear in the property box 

Existing shear capacity in beam as per drawing (As per IS - 456 - 2002 clause 40.4 )

      Vus = 0.87 fy Asv d/Sv 

          Fy= 415 N/mm^2 

          Asv = 151 mm^2 

         d = 450 mm 

         Sv = 100 mm 

          Vus =245 kN 

 Hence shear rebar in drawing is Okay as per IS - 13920 code guidance