Project on Concrete Mix Design for various grades of Concrete
Environment Exposure Condition : Severe, Cement: OPC-43 Grade, Max Aggregate size Zone 2: 20mm, min Cement : 320 kg/m3, W/C ratio - 0.4, Workability : 100mm (Pumpable) Specific Gravity of Cement: 3.25, Super Plastizer added
1)Target Mean Strength: f'ck=fck+1.65s= 35+(1.65x5)=43.25 N/mm2
2)Selection of Water Content for Slump 100mm from table 2 of IS 10262:2009 : 186+(6/100x 186)=197.16 lit
3)Super plastizer reduces water by 29% = 0.71x197.16= 140 lit
4)Calculation of cement content = W/C =0.4 = 140/0.4=350 kg/m3>320 kg/m3
5) Cementitious material can be increased by 10%= 350x 1.1= 385kg/m for Fly ash addition
6) fly ash 30�mentitious = 30x 385/100= 115.5 kg/m3
7) Cement content = 385-115.5= 269.5 kg/m3
8)Proportion of C.A & F.A = Table of IS 10262:2009
As w/c ratio lower by 0.1 the proportion of volumne of C.A is increased by 0.02= 0.62+0.02=0.64
9)Pumpable concrete reduced by 10% therefore volume of C.A = 0.64x0.9=0.576,
volume of Fine Aggregate=1-0.576=0.424
10) Mass of Chemical Admixture =2%of Cementitious material= 269.5x2/100= 5.39 kg
a) Volumne of Concrete = 1m3
b) Volune of Cement = (Mass of Cement/Specific Gravity)x(1/1000)=(269.5/3.25)x(1/1000)=0.082m3
c) Volumne of Water = (Mass of Water/Specific Gravity)x(1/1000) = (140/1)x(1/1000)=0.14m3
d) Volumne of Admixture = (Mass of Admixture/Specific Gravity)x(1/1000) =
(5.39/1.145)x(1/1000)= 0.004m3
e) Volume of Flyash = (Mass of Fly Ash/Specific Gravity)x(1/1000) = (115.5/2.3)x (1/1000)=0.050m3
f) Volume of Aggregate = { a-[b+c+d+e]} = {1-[0.082+.14+0.004+0.050]} = 0.724m3
g) Mass of Coarse Aggregate = e x ratio of C.A x Specific gravityx 1000= 0.724x0.576x 2.74x 1000=1142.64 kg
h) Mass of F.A = e x ratio of F.A x Specific gravityx 1000= 0.724 x 0.424x 2.74x 1000 = 841.11 kg
Cement = 269.5 kg, Fly Ash = 115.5 kg, Admixture = 5.39 kg, water = 140 lit, W/C = 0.4
Coarse Aggregate = 1142.64 kg, Fine Aggregate = 841.11 kg
M35 Grade Trial Mix Ratio = 1:3.12:4.23 ( Fly Ash = 7kg, Slump=100mm, Admixture=5.39kg)
Environment Exposure Condition : Severe, Cement: OPC-43 Grade, Max Aggregate size Zone 2: 20mm, min Cement : 320 kg/m3, W/C ratio - 0.4, Workability : 100mm (Pumpable) Specific Gravity of Cement: 3.25, Super Plastizer added
1)Target Mean Strength: f'ck=fck+1.65s= 50+(1.65x5)=58.25 N/mm2
2)Selection of Water Content for Slump 100mm from table 2 of IS 10262:2009 : 186+(6/100x 186)=197.16 lit
3)Super plastizer reduces water by 29% = 0.71x197.16= 140 lit
4)Calculation of cement content = W/C =0.3 = 140/0.3=466.66 kg/m3>320 kg/m3
5) Cement content = 466.66 kg/m3
6)Proportion of C.A & F.A = Table of IS 10262:2009
As w/c ratio lower by 0.1 the proportion of volumne of C.A is increased by 0.02= 0.62+0.02=0.64
7)Pumpable concrete reduced by 10% therefore volume of C.A = 0.64x0.9=0.576,
volume of Fine Aggregate=1-0.576=0.424
8) Mass of Chemical Admixture =2%of Cementitious material= 466.66x2/100= 9.33 kg
a) Volumne of Concrete = 1m3
b) Volune of Cement = (Mass of Cement/Specific Gravity)x(1/1000)=(466.66/3.25)x(1/1000)=0.143m3
c) Volumne of Water = (Mass of Water/Specific Gravity)x(1/1000) = (140/1)x(1/1000)=0.14m3
d) Volumne of Admixture = (Mass of Admixture/Specific Gravity)x(1/1000) =
(9.33/1.145)x(1/1000)= 0.008m3
f) Volume of Aggregate = { a-[b+c+d]} = {1-[0.143+.14+0.008]} = 0.709m3
g) Mass of Coarse Aggregate = e x ratio of C.A x Specific gravityx 1000= 0.709x0.576x 2.74x 1000=1118.97 kg
h) Mass of F.A = e x ratio of F.A x Specific gravityx 1000= 0.709 x 0.424x 2.74x 1000 = 823.68 kg
Cement = 466.66 kg, Admixture = 9.33 kg, water = 140 lit, W/C = 0.3
Coarse Aggregate = 1118.97 kg, Fine Aggregate = 823.68 kg
M50 Grade Trial Mix Ratio = 1:1.76:2.39 ( Slump=100mm, Admixture=9.33kg)