Challenge

Project on Concrete Mix Design for various grades of Concrete

AIM: To calculate the concrete mix design for M35 concrete with fly ash. And concrete mix design of M50 concrete mix without fly ash.

EQUATIONS: Target main strength Fck = fck + 1.65

PROCEDURE AND CALCULATION :

1. TARGET MEAAN STRENGTH

f'ck = fck = 1.65

fck = 35 n/mm2 (M35 concrete)

s = 5 N/mm2

fck = 35 + (1.65 x 5) = 43.25 n/mm2

2. SELECTION OF WATER CEMENT RATIO

M35 concrete

extreme = w/c ratio = 0.40

M35 = w/c ratio = 0.45

lower water content for better workability 0.40<0>

water cement ratio = 0.40

minimum cement content = 360 kg/m3

3. SELECTION OF WATER CONTENT

NOMINAL SIZE OF AGGREGATES = 20mm

minimum water content = 186 litres

slump ranges feom 25mm to 50mm

as superplasticizers (20% reduced) = 186 x 80/100 =148.8 so the water content is 149 litres

4. CALCULATON OF CEMENTITIOUS CONTENT

W/C ration = 0.40

water content= W =149 kg

cementitious content= c=149/0.40= 372.5 = 370 kg/m3

minimum cement content = 360 kg/m3, 360<370>

370 x 0.10 + 370 = 407 kg/m3

W = 149 kg

w/c ratio = 149/407 = 0.366

fly ash at 30% total cementitious material content = 407 x 30/100 = 122 kg/m3

saving of cement while using fly ash = 370 - 285 = 85kg/m3

fly ash = 122kg/m3

5. VOLUME OF COARSE AND FINE AGGREGATES

coarse aggregates are seived according to table 2 IS 383

fine aggregates are seived according to table 2 IS 383

therefore nominal size of coarse aggregate is 20mm and fine aggregate should be zone 1

and the volume of coarse aggregate = 0.60

w/c ratio = 0.4 (=/- 0.01 for every +/- 0.005)

so the volume of coarse aggregate is 0.62

volume of fine aggregate = 1 - 0.62 = 0.38

6. MIX CALCULATION

VOLUME OF CONCRETE = 1m3

volume of cement = (285/3.15) x 1/1000 = 0.090 m3

volume of fly ash = (122/2.2)x(1x1000) = 0.055m3

volume of water = (149/1)x1/1000 = 0.149 m3

volume of admixture = (7.6/1.145)x1/1000 = 0.006 m3

volume of coarse and fine aggregate = a - (b + c + d +e ) = 1 - ( 0.090 + 0.149 + 0.006) + 0.7 m3

mass of coarse aggregate = 1189.16 kg/m3

mass of fine aggregate = 728 kg/m3

RESULT AND CONCLUSION:

cement = 285 kg/m3

fly ash = 122 kg/m3

water = 149 kg/m3

coarse aggregate = 1189 kg/m3

fine aggregate = 728 kg/m3

chemical admixture = 7.6 kg/m3

w/c ratio = 0.366

trial mix ratio : 285:728:1189 = 1:2.55:4.17(C:FA:CA)

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