Project on Concrete Mix Design for various grades of Concrete
Calculate the Concrete Mix Design for M35 grade concrete with fly ash?
1. Target mean strength of concrete:
f'ck = fck+1.65*S
f'ck 35+1.65*5
=43.25 N/mm2
2. Selection of water cement ratio:
Maximum cement ratio= 0.45 (From table 5 of IS 456-2000)
On experience water cement ratio is 0.4
0.4<0.45
Hence ok.
3. Selection of water content:
The maximum water content for 20mm aggregate is 186 It.
For 100mm slump = 186+(6/100) *186
= 197 It
As superplasticizer is used the water content is reduced to 29%
Hence water content = 197*0.7
= 140 It
4. Selection of cement content:
W = 140 kg
w/c = 0.4
C = w/0.4
C = 140/0.4
= 350 kg/m3
350 > 320
Hence ok
The fly ash is used.
So it increases 10% cementatious
material content.
350*1.1 = 385 kg/m3
Fly ash at 30% total cementatious material is
35-30% 115 kg/m3.
5. Volume of coarse aggregate and fine aggregate content:
For 20mm aggregate the volume of
coarse aggregate is 0.64 as per table
3 IS 10262:2009
For pumpable concrete, these are reduced by 10%
Volume of coarse aggregate =
0.64*0.9
= 0.576
Volume of fine aggregate = 1-0.576
= 0.424
6. Mix calculation:
Volume of concrete = 1m3
Volume of cement = 0.086 m3
Volume of water = 0.140 m3
Volume of chemical admixture = 0.006 m3
Volume of aggregate (FA&CA) = 0.716 m3
Mass of coarse aggregate = 1130 kg/m3
Mass of fine aggregate = 831 kg/m3
Volume of flyash = 0.052 m3
7. Mix proportion:
Cement = 270 kg/m3
Water = 140 kg/m3
Fly Ash = 115kg/m3
Fine aggregate = 831 kg/m3
Coarse aggregate = 1130 kg/m3
Chemical admixture = 7 kg/m3
Water cement ratio = 0.364
Mix Ratio = 1:2.15:2.94
Calculate the concrete mix design for M50 grade concrete without flyash?
1. Target mean strength of concrete:
f'ck = fck+1.65*S
= 50+1.65*5
= 58.25 N/mm2
2. Selection of water cement ratio:
As per IS 456-2000, table 5,
Water cement ratio is 0.4.
3. Selection of water content:
The maximum water content for 20mm aggregate is 186 It.
For 100mm slump = 186+(6/100) *186
= 197 It
As superplasticizer is used the water content is reduced to 29%
Hence water content = 197*0.7
= 140 It
4. Selection of cement content:
Water cement ratio = 0.4
Cement content = 140/0.4
= 350 kg/m3
From table 5 of IS 456-2000,
The cement content is 320 kg/m3
350>320 kg/m3
Hence ok.
5. Volume of coarse aggregate and fine aggregate content:
The corrected value of coarse aggregate for water cement ratio is 0.64.
For pumpable concrete, these are reduced by 10%.
Volume of coarse aggregate = 0.64*0.9
= 0.576
Volume of fine aggregate = 1-0.576
= 0.424
6. Mix Calculation:
Volume of concrete = 1 m3
Volume of cement = 0.111 m3
Volume of water = 0.140 m3
Volume of chemical admixture = 0.006 m3
Volume of aggregate (FA&CA) = 0.743 m3
Mass of coarse aggregate = 1173 kg/m3
Mass of fine aggregate = 863 kg/m3
7. Mix proportion:
Cement = 350 kg/m3
Water = 140 kg/m3
Fine aggregate = 863 kg/m3
Coarse aggregate = 1173 kg/m3
Chemical admixture = 7 kg/m3
Water cement ratio = 0.4
Mix Ratio = 1:2.46:3.35