Challenge

Project on Concrete Mix Design for various grades of Concrete

Concrete mix design for M35 grade concrete with flyash

Target mean strength for mix proportions:

f'ck=fck+1.65*S

=35+1.65*5=43.25N/mm^2

Selection of water cement ratio:

From table 5 of IS 456:2000 for severe condition

maximum water cement ratio =0.45

Based on experience adopted water cement ratio is 0.40

0.40<0.45,hence ok

Selection of water content:

from table 2 of IS 10262:2009,

max water content for 20mm aggregate=186 litre (For 25mm to 50 mm slump range)

Estimated water content for 100 mm slump =186+6/100*186=197 litre.

As flyash is using,the water content can be reduced upto 20% and above

Based on trials water content reduction of 29% is achieved with flyash

Hence the arrived water content =197*0.71=140 litre

Calculation of cement content:

water cement ratio=0.4

cement content =140/0.4=350 kg/m^3

From table 5 of IS 456 minimum cement content for severe exposure condition 320kg/m^3

350kg/m^3>320kg/m^3,hence ok.

Now to proportion a mix containing flyash the following steps are suggested:

a) The percentage of flyash needs to be decided based on project requirement and quality of materials.

b) In some cases icrease in cementitious material can be warranted.

Cementitious material content=350*1.10=385 kg/m^3

water content =140kg/m^3

so,w/c ratio =140/385=.364

Flyash @ 30 % total cementitious materail content=385*30%=115kg/m^3

cement =385-115 =270 kg/m^3

saving of cement while using flyash 350-270=80kg/m^3

Flyash being utilized =115 kg/m^3

Proportion of volume of CA & FA

From table 3 of IS 10262:2009,volume of CA corresponding to 20 mm size aggreate FA for w/c ratio of 0.5=0.6

In the present case the w/c is=0.4

Therefore the volume of CA needs to be increased to decrease the FA content.

Corrected volume of CA for the w/c ratio of 0.4=0.62

therefore volume of CA =0.62*0.9=0.56

volume of FA content =1-0.56=0.44

Mix calculations

The mix calculation per unit volume of concrete shall be as follows:

Volume of concrete =1m^3

Volume of cement=Mass of cement/sp. gr. of cement*1/1000=270/3.15*1/1000=0.085m^3

Volume of water=mass of water/sp gr of water*1/1000=140/1*1/1000=0.140M^3

Volume of chemical admixture=7/1.145*1/1000=0.006m^3

Volume of aggregate=1-(0.085+0.140+0.006)=0.769m^3

Mass of coarse aggregate=0.769*0.56*2.74*1000=1140kg/m^3

Mass of fine aggregate=0.769*0.44*2.74*1000=896kg/m^3

Mix proportions for trial no

cement=270kg/m^3

Flyash=115kg/m^3

water=140kg/m^3

FA=896kg/m^3

CA=1149kg/m^3

w/c ratio=0.364

Concrete mix design for M50 grade concrete without flyash

Target strength for mix proportions:

f'ck=fck+1.65*S=50+1.65*5=58.25N/mm^2

selection of water cement ratio:

From table 5 of IS 456:2000 for severe exposure,

max water cement ratio=0.45

Based on experience,adopted w/c ratio is 0.40.

0.40<0.45,hence ok.

Selection of water content:

from table 2 of IS 10262:2009,

max water content for 20 mm aggregete=186 litre

As superplasticizer is used,the water content can be reduced upto 20% and above

Baseed on trials water content reduction of 29% is achieved with plasticizer

Hence the arrived water content=186*0.71=132litre

Calculation of cement content:

w/c ratio=0.4

cement content=132/0.4=330 kg/m^3

from table 5 of IS 456:2000 min cement content for severe exposure condition=320kg/m^3

330kg/m^3>320kg/m^3,Hence ok.

Proportion of volume of CA & FA

From table 3 of IS 10262:2009,volume of CA corresponding to 20mm size aggregate & FA for w/c artio of 0.5=0.6

In the preseent case the w/c ratio is =0.4

Therefore the volume of CA needs to be increased to decrease the FA content.

As w/c ratio is lower by0.10,the proportion of volume of CA is increased by 0.02

Therefore corrected volume of CA for the w/c ratio of 0.40 is 0.62.

volume of FA content=1-0.62=0.38

Mix calculations:

The mix calculation per unit volume of concrete shall be as follows:

Volume of concrete=1m^3

Volume of cement=330/3.15*1/1000=0.105m^3

Volume of water=132/1*1/1000=0.132m^3

Volume of chemical admixture=7/1.145*1/1000=0.006m^3

Volume of aggregate=1-(0.105+0.132+0.006)=0.757m^3

Mass of CA=0.757*0.62*2.74*1000=1285kg/m^3

Mass of FA=0.757*0.38*2.74*1000=788.2kg/m^3

Mix proportions for trial number

cement=330kg/m^3

water=132kg/m^3

FA=788.2kg/m^3

CA=1285kg/m^3

chemical admixture=7kg/m^3

w/c ratio =0.4

Trial mix ratio=1:2.39:3.89

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