Project on Concrete Mix Design for various grades of Concrete
1.Mix design for M35 grade concrete with flyash
- Mix proportioning of concrete using flyash as part of replacement of OPC
Stipulation for proportiong.
- Grade designation :M35
- Type of cement :OPC43 grade
- Type of mineral admixture : flyash conforming to IS8112
- Maximum nominal size of aggregate :20mm
- Minimum cement content :320kg/m^3 (From table 5 of IS456:2000)
- Maximum water cement ratio : 0.45
- Workability : 100mm (slump value for pumpable concrete.
- Exposure condition : Severe for rcc
- Method of concrete placing:pumping
- degree of supervision : Good
- Type of Aggregate : Crushed angular aggregate
- Maximum cement content :450kg/m^3
Test data for materials:
- cement used :OPC 33 grade conforming to IS8112
- Specific gravity of cement :3.15
- Flyash : Conforming to IS 3812 (part 1)
- Specific gravity of flyash : 2.2
- Chemical admixture : Superplasticizer confoming to IS 9103
- Specific gravity of
coarse aggregate :2.74
fine aggregate : 2.74
g.Water Absorption
Coarse Aggregate : 0.5%
Fine Aggregate :1.0%
h.Free Surface moisture
Coarse Aggregate : Nill
Fine Aggregate : Nill
Sieve Analysis
Coarse Aggregate: conforming to table 2 os IS 383
Fine aggregate :conforming to grade Zone II of table 4 of IS 383
TARGET STRENGTH FOR MIX PROPORTIOING:
f'ck = fck + 1.65 S
when f'ck = target average compresive stregth at 28 days.
fck = Charateristic compressive stregh of 28 days.
S = Standard deviation.
From Table I of IS 10262:2009 standard deviation
S = 5 N/mm^2
Target Strength = 35+(1.65*5)
= 35+(8.25)
= 43.25
SELECTION OF WATER CEMENT RATIO:
from table 5 of IS 456:2000 for severe exposure, maximum water cement ratio as 0.45
SELECTION OF WATER CONTENT
from table 2 of IS 10262:2009 maximum water content for 20mm aggregate = 186 lit (25mm to 50mm slump range)
Estimated water content for 100 mm slump = 186 + 6/100*186 = 197 lit.
As superplasticizer is used, the water content can be reduced upto 30% based on trail water content reduction 29% is achived with plasticizeer.
Hence arrived water content = 197 * 0.71 = 140 litre
CALCULATION OF CEMENT CONTENT
water cement ratio = 0.45
Cementitious material ( Cement +flyash ) content
= 140 / 0.45 = 311kg/m^3
From Table 5 of minimum cement content for severe exposure condition = 320kg/m^3
320kg /m^3 > 311kg / m^3 Hence ok.
Now to proportion a mix containting flyash the following steps are suggested.
Hence 320 OK
Cementitious material content = 320 x 1.10 = 352kg/m^3
water content = 140kg/m^3
So, water content ratio = 140/352 = 0.394
flyash @30% total cementitious material content = 352*30% = 105m^3
Cement OPC = 352 - 105 = 247 kg/m^3
Saving of cement while using flyash = 320-247 = 73kg/m^3
Flyash being utilized = 105 kg/m^3
PROPOTION OF COARSE AND FINE AGGREGATE
From table 3 of IS 10262:2009 (in zone 1) water cement ratio of 0.5 = 0.6
Volume of coarse aggregate = 0.62x 0.9 = 0.56
Volume of Fine aggregate = 1 - 0.56 = 0.44
Mix calculation
Volume of concrete = 1M^3
Volume of cement = 247 / 3.15*1/1000 = 0.0784M^3
Voume of flyash = 105/2.2*1/1000 = 0.047
Volume of water = 140/1*1/1000 = 0.140M^3
Volume of chemical admixture = 7.6/1.145 * 1/1000 = 0.006M^3
Volume of aggregate (FA &CA) = (1-(0.0784+0.047+0.140+0.006)) = 1-0.2714 = 0.728M^3
Mass of Coarse aggregate = 0.728 * 0.56 *2.74 * 1000 = 1117kg/M^3
Mass of fine aggregate = 0.728 *0.44*2.74*1000 = 877kg/m^3
MIX PROPORTION
cement = 247 kg/m^3
flyash = 105
water = 140
Fine aggregate = 877
coarse aggregate = 1117
Chemical admixture = 7kg/m^3
Water cement ratio = 0.39
so mix ratio = 1:2.49:3.17
M50 GRADE CONCRETE MIX WITHOUT FLYASH
- Grade : M50
- type of cement : OPC 53
- maximum nominal size of aggregate : 20 mm
- minimum cement content : 320 kg/m^3 (table5)
- maximum water content. : 0.45 (table5)
- wokability :100 mm slump
- maximum cement content :450 kg/m^3
target mean strength f ck = 50+1.65x5= 58.25 n/mm^2
water cement ratio from table 5 = .44
slump for 100mm = 186+(6/100)x186= 197 lit
based on trials 29% reduced for plasticier= 197x0.71 =140 lit
caculation of cement required
cement content 140/.44= 318 kg/m^3
320 > 318 kg/m ^3 ok
so cement required is 320 kg/m^3
mix calculation
- voulume of concrete =1m^3
- vol of cement = 320/3.15 x 1/1000 =0.101 m^3
- vol of water. = 140/1x1/1000. =0.14 m^3
- vol of chemical admix =7.6/1.145 x1/1000 = .006 m^3
- vol of all aggregate. =1- (0.101+0.14+.006) =0.753 m^3
- vol of coarse aggregate =0.753x0.568x2.74x1000= 1172 kg/m^3
- vol of fine aggregate. =0.753x0.431x2.64x1000= 857 kg/m^3
MIX PROPORTIONS
- CEMENT 320 kg/m^3
- WATER. 140 l/m^3
- FINE AGGREGATE. 857 kg/m^3
- COARSE AGGREGATE 1172 kg/m^3
- CHEMICAL ADMIXTURE 7.18 kg/m^3
- WATER CEMENT RATIO 0.44
MIX PROPORTION 1:2.67:3.66