Challenge

Project on Concrete Mix Design for various grades of Concrete

CONCRETE MIX DESIGN FOR M35 GRADE CONCRETE WITH FLY ASH:

  1. Stipulations for proportioning:

a) Grade designation : M35

b) Type of cement : OPC 53 Grade conforming to IS 8112

c) Type of admixture : Fly ash

d) Max. nominal size of aggregate : 20mm

e) Min. cement content : 340kg/m^3 [From table IS 456]

f) Max.cement content : 450kg/m^3 [As per code]

g) Partial replacement of cement by Fly ash : 30% [As per requirement]

h) Max. water-cement ratio : 0.45 [From IS 456]

i) Workability : 100mm

j) Chemical admixture : PCS Type

2. Test data for materials:

a) Cement used : OPC 53 Grade conforming to IS 8112

b) Specific gravity of cement : 3.15

c) Mineral admixture : Fly ash [Confirming to IS12089]

d) Specific gravity of fly ash : 2.90

e) Chemical admixture : @0.6% [IS9103 ]

f) Specific gravity

- Coarse aggregate : 2.74

- Fine aggregate : 2.74

- Admixture PCE based : 1.12

g) Water absorption

- Coarse aggreagte : 0.5%

- Fine aggregate : 1.0%

h) Sieve analysis

- Coarse aggregate [Confirming to Table 2-IS383]

- Fine aggregate : Zone II [Confirming to Table 2-IS383]

3. Target strength for mix proportions:

Fck = fck + 1.65s ['S' from table I of IS10262]

= 35 + 1.65*5

Fck = 43.25 N/mm^2

4. Selection water-cement ratio:

From table 5 of IS456,

Max. water-cement ratio = 0.45

Based on experience, adapted water-cement ratio = 0.45

5. Selection of water content:

From table 2 of IS10262:2009,

Max. water content for 20mm aggregate = 186lts [for 25 to 50mm slump range]

Water content for 100mm slump = 186+6/100*186

= 197.16lts

As superplasticizers are used water content can be reduced upto 20%,

Water content requirement after SP = 198-(0.20*198)

= 157.73

Adopted water content = 160lts

6. Calculation of cement and fly ash content:

Water-cement ratio = 0.45

Total cementious (cement+fly ash) requirement = water content/water-cement ratio

= 160/0.45

= 355.55kg

Since Fly ash is used the amount of Cementitious content (Cement+Fly ash) shall be increased to get good workability and strength. Here we increased the cementitious content by 1.1 %.

Final cementious content (Cement+fly ash) = 356*1.1

= 391.6kg

Min. cement content required for severe exposure = 340kg [as per IS456 Table5]

Adapted cementious content = 391.6kg >340kg

Fly ash content requirement = 391.6*0.30 [30% replacement]

= 117.48 - 118kg

Cement content requirement = Cementious content-Fly ash

= 391.6-117.48

= 274.12

Calculation of Super Plasticiers @ 0.6 percent to the mass of cementitious content = = 391.6* (0.6/100) = 2.35 kg

7. Coarse and fine aggregate:

Coarse aggregate ratio = 0.62 [From IS10262 table 3 w/c 0.5]

Coarse aggregate ratio for 0.45 w/c ratio = 0.63

Final fine aggregate ratio = (1-0.63) = 0.37

8. Mix calculations for M35 grade:

a) Volume of concrete = 1m^3

b) Volume of cement = mass of cement/(S.G*1000)

= 275/(3.15*1000)

= 0.087 m^3

c) Volume of water = mass of water/(S.G*1000)

= 160/(1*1000)

= 0.160m^3

d) Volume of Fly ash = mass of fly ash/(S.G*1000)

= 118/(2.5*1000)

= 0.041m^3

e) Volume of superplasticizers = 2.35/(1.12*1000)

= 0.002m^3

f) Volume of aggregate = [a-(b+c+d+e)]

= [1-(0.087+0.04+0.160+0.002)]

= 0.71m^3

g) Mass of coarse aggregate = e*vol. of C.A*S.G*1000

= 0.71*0.63*2.74*1000

= 1225.6kg

h) Mass of fine aggregate = 0.71*0.37*2.74*1000

= 719.8kg

9. Mix proportions for M35 grade concrete:

Cement = 275kg

Fly ash = 118kg

Fine aggregate = 720kg

Coarse aggregate = 1226kg

Water =160L

PCE based super plasticizer = 2L

Therefore Mix Ratio of M35 Grade concrete by weight is,

Cement : Flyash: F.A : C.A : Water = 1:0.4:2.6:4.46:0.58

MIX DESIGN FOR M50 GRADE CONCRETE WITHOUT FLY ASH:

  1. Stipulations for proportioning:

a) Grade designation : M50

b) Type of cement : OPC 53 Grade conforming to IS 8112

c) Max. nominal size of aggregate : 20mm

d) Min. cement content : 320kg/m^3 [From table IS 456 Exposure condition]

e) Max.cement content : 450kg/m^3 [As per code]

f) Max. water-cement ratio : 0.45 [From IS 456]

g) Exposure condition : Severe (For reinforced concrete)

i) Workability : 100mm

j) Chemical admixture : Super plasticizer

k) Method of concrete placing : Pumping

l) Degree of supervision : Good

m) Type of Aggregate : Crushed angular aggragates

2. Test data for materials:

a) Cement used : OPC 53 Grade conforming to IS1229-1989

b) Specific gravity of cement : 3.15

c) Chemical admixture : Super plasticizer conforming to IS1903

d) Specific gravity of CA : 2.74

e) Specific gravity of FA : 2.64

f) Water absorption of CA : 0.5%

g) Water absorption of FA : 1.0%

h) Free surface moisture of CA : Nil

i) Free surface moisture of FA : Nil

j) Sieve analysis: CA : Conforming to table 2 of IS383

k) Sieve analysis: FA : Conforming to grading zone II of table IS383

3. Target strength for mix proportioning:

f'ck=fck+1.65s

From table 1 of IS 10262:2009,

Standard deviation, s = 5 N/mm^2

f'ck = 50+1.65(5)

= 58.25 N/mm^2

4. Selection of water-cement ratio:

Maximum w/c ratio=0.45

It can be found from table 5 of IS456-2000 for severe exposure

Based on experience, adopted w/c ratio 0.44

0.44<0.45, hence ok

Adopted w/c ratio 0.44

5. Selection of water content:

From table 2 of IS 10262:2009 Max. water content for 20mm aggregate,

186litre (for 25 to 50mm slump range)

Increasing 3% of water content for every extra 25mm slump from 50mm slump so 6% is to added to it

186+(6/100)*186 = 197 litre

Estimated water content for 100mm slump,

if superplasticizer used 20% the water content is to be reduced up to and above

Based on trials with super plasticizer water content reduction of 20% has been achieved,

Hence the water content arrived

197*0.8 = 158lts

Water required = 158litres

6. Calculation of cement required:

Adopted w/c ratio = 0.44

Cement content = 158/0.44 = 359kg/m^3

From table 5 of IS 456, Min. cement content for Severe exposure conditions,

320>359kg/m^3 Hence ok

Cement required 359kg/m^3

7. Volume of coarse and fine aggregate content:

From table 3 of IS 10262:2009 volume of coarse aggregate corresponding to 20mm size aggregate and fine aggregate (zone II) for w/c ratio is 0.50 0.62

In the present case w/c ratio is 0.44. Therefore volume of coarse aggregate is to be increased to decreased on fine aggregate content. As the w/c ratio is lower by 0.06. The proportion of volume of coarse aggregate is increased by 0.02

Therefore corrected portion of volume of coarse aggregate for w/c ratio is 0.44 0.632

For pumpable concrete these values should be reduced upto 10%. Therefore volume of coarse aggregate

0.632x0.9 = 0.568

Volume of fine aggregate 1-0.576 = 0.431

Volume of fine aggregate and coarse aggregate is 0.431 and 0.568

8. Mix calculations:

a) Volume of concrete = 1m^3

b) Volume of cement = mass of cement/(S.G*1000)

= 359/(3.15*1000)

= 0. m^3

c) Volume of water = mass of water/(S.G*1000)

= 158/(1*1000)

= 0.158m^3

e) Volume of Chemical admixture = 7.6/(1.145*1000)

= 0.006m^3

f) Volume of aggregate = [a-(b+c+d+e)]

= [1-(0.114+0.158+0.006)]

= 0.722m^3

g) Mass of coarse aggregate = e*vol. of C.A*S.G*1000

= 0.722*0.56*2.74*1000

= 1123kg

h) Mass of fine aggregate = 0.722*0.431*2.74*1000

= 821kg

9. Mix proportions for M50 grade concrete:

Cement = 359kg

Fine aggregate = 821kg

Coarse aggregate = 1123kg

Water =158l

W/c ratio = 0.44

Chemical admixture = 7.18

Mix Proportion by weight = 1:2.28:3.12

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