Project on Concrete Mix Design for various grades of Concrete

MIX DESIGN FOR M35 GREDE OF COCRETE WITH FLY ASH

The mix design for m35 grade cocrete fpr the pile foundation provided here for the reference purpose only.actul site conditions vary thus thios should be advised as per the locations and other factors.

1)PRPORATION FOR M35 GRADE OF CONCRETE

• Grade disignation =M35
• type of cememt=OPC 53
• type of admixtures=fly ash
• Maximum nominal size of aggregates=20mm
• Manimum cement content=340kg
• maximum cement content =450kg
• partial replacement of cement by flyash=30%
• maximum w/c ratio =0.45
• workablity =100mm

2)TESTED DATA FOR MATERIALS

• Cement used OPC 53 conforming IS 8112
• Specific gravity of cement=3.15
• mineral admixtures=Fly ash
• specific gravity of fly ash=2.90
• chemical admixtures [email protected]%
• specific gravity of c.a=2.74
• specifi gravity for f.a=2.74
• admixtures PCE based=1.12
• water absorption on c.a=0.5%
• water absorption on f.a=1%

3)TARGET STRENGTH FOR MIX PROPERATIONS OF M35 GRADE CONCRETE

The strength of cocrete may be vary depending on the quality of material the mixing mrthod and the construction producers.therefore the target sterngth (Fck)must be greater than the rquired strength of cocrete.

Fck=fck+1.65s

= 35+1.65*5

=43.25N/mm2

4)SELECTION OF WATER CEMENT RATIO

The maximum water cement ratio for different gradesis given for table5-IS456.you can reduce the w/c ratio based on your needs.

the water cement ratio directly affected on the strength of the concrete

Maximum water cement ratio =0.45

adopted water cement ratio=0.45

5)SELECTIN OF WATER CONTENT

Maximum water content =186L

The water content above the slump of 25 to 50mm.,

incresed by 6%

=water content for 100mm slump =186+(0.06*186)

=197.16L

percentage of reduction water =20%

Water content required after SP=198-(0.20*198)

=157.73L

Adopted water content =160L

6)CALCULATION OF CEMENT AND FLY ASH CONTENT

Adopted water cement ratio=0.45

Total cementitionus(cement+flyash)reqirement=Water content/water cement ratio

=160/0.45=355.55kg

final cementitious content=356*1.10=391.6kg

minimum cement content require "serve"expore=340 kg (IS 456 Table-5)

Adopted cementitious content =391.6kg

Fly ash requirement =391.6*0.30

=117.48=118kg

cement content reqired=Cementitious content - flyash

=391.6-117.48=274.12

6)COARSE AND FINE AGGREGATE

Coarse aggergete ratio=0.62

coarse aggregate for 0.45w/c ratio=0.63

Final fine aggregate ratio =0.37 hence(1-0.63=0.37)

7)MIX CALCULATIONS FOR M35 GRADE OF CONCRETE

1. Volume of concrete=1cum3
2. total volume of cement=cement/S.G*1000

=275/(3.15*1000)

=0.087 CU.M

3.Total volume of flyash=fly ash/S.G*1000

=118/(2.5*1000)=0.041CU M

4.Volume of water=water/S.G*1000

=160/1*1000=0.160cu.m

5.volume of super plsticizers=superplasticizer/S.G*1000

=2.35/(1.12*1000)=0.002cu.m

6.Total aggregates requirements=A-(B+C+D+E)

=1-(0.87+0.041+0.160+0.002)

=0.71 cu.m

7.Coarse aggregate(C.A)=F*C.A Ratio*S.G*1000

=0.71*0.63*2.74*1000=1225.6KG

8.Fine aggregates(F.A)=F*F.Aratio*S.G*1000

=0.71*0.37*2.74*1000=719.8KG

CEMENT,FLYASH,SAND,AGGREGATES AND SPERPLASTICIZERNEEDED FOR M35 GRADE CONCRETE

• Cement =275kg
• flyash=118kg
• fine aggregate=720kg
• coarseaggregate(20mm)=1226kg
• water=160L
• PCE based superplasticizer=2L

RESULT

in the ratio of M35 grade concrete= 1:0.4:2.6:4.46:0.58

(II)DESIGN MIX FOR M50 GRADE CONCRETE WITHOUT FLYASH

The design M50 grade concrete provide based on reqirements to chenging values on mixtures

MIX DESIGN

• Grade of concrete=M50
• type of cement=OPC
• spcific gravity

1. cement=3.15
2. F.A=2.61
3. C.A=2.66
4. Cement =400kg/m3
5. w/c ratio=0.45

MIX CALCULATIONS

• Target mean strength =Fck+1.65*SD
• =50+(5*1.65)=58.25mpa
• W/C ratio =0.35
• calculation of water=180*0.8=144kg(20 mm aggregate max size)
• calculation of cement comntent

w/c ratio=0.35

water content per cu m=144kg

cement content=144/0.35=411.4kg=412kg

CALCLATION FOR C.A AND F.A

• Volume of concrete=1m3
• volume of cement=412 kg/m3
• volume of water=144/1*1000=0.1440m3
• volume of admixtures=4.994/1.45*1000=0.0043m3
• Total weight of aggregate =0.1308+0.1440+0.0043=0.2741m3
• volume of C A and FA =1-0.2791=0.7290M3
• Volume of FA=0.7209*0.33=0.2379m3

voliume of F.A

=0.7209-0.2379=0.4830m3

therefore weight of CA

=0.2379*261*1000 =621kg/m3

weight of C.A

0.4830*2.655*1000=1282.365Kg/m3

considering 20mm and 10mm=0.55:0.45

20mm=706kg

10mm=578kg

RESULT

HENCE MIX DETAILS FOR 1 M3

• CEMENT =422KG
• WATER=147.6KG
• FINE AGGREGATE=621KG
• COURSE AGGREGATE 20 MM=706KG
• 10MM COURSE AGGREGATE=578KG
• ADMIXTURES=1.2%OF CEMENT=5.04

RATIO OF MIX=1:1.472:3.043

WATER CEMENT RATIO=0.35