Challenge

Project on Concrete Mix Design for various grades of Concrete

Concrete Mix Design for M35 grade concrete with fly ash

1.Stipulations for proportioning

A Grade Designation M35
B Type of Cement OPC 53
C Type of Admixture Fly ash
D Maximum Nominal
Size of Aggregate
20mm
E Minimum Cement Content 340kg IS 456
F Maximum Cement Content 450kg As per code
G Partial replacement
of cement by Fly ash
30% as per requirement
H Maximum W/C ratio 0.45 IS 456
I Workability 100mm
J Chemical Admixture PCS Type

2.Test data for materials

A Cement Used OPC 53 Confirming to
IS8112
B Specific Gravity of Cement 3.15 IS: 2720
C Mineral Admixture Fly ash Confirming to IS12089
D Specific Gravity of Fly ash 2.90
E Chemical Admixture 0.6% IS9103
F Specific Gravity of IS 2386
Coarse Aggregate 2.74
Fine Aggregate 2.74
Admixture PCE based 1.12
G Water Absorption IS 2386
Coarse aggregate 0.5 %
Fine aggregate 1 %
H Sieve Analysis IS 2386
Coarse aggregate Confirming to
Table 2-IS383
Fine aggregate Zone II Confirming to
Table 4-IS383

3.Target strength for mix proportions

Fck= fck+1.65*S

Value of standard deviation(s) for different grade of concrete is taken from in Table 1 of IS456.

Fck =35+1.65*5=43.25 N/mm^2.

4.Selection of water ceement ratio

The maximum water-cement ratio for M35 grade of concrete is taken from in Table 5-IS456.

The maximum water cement ratio =0.45

Adopted water cement ratio =0.45.

5.Selection of water content.

Maximum water content = 186 litre.

Above water-content is for 25 to 50mm slump but the slump we require is 100mm. hence we need to increase the water content to get the required slump for good workability. Clause 4.2 of IS1026 suggests an increase of 3% of water content from its original value for every increase of 25mm. Here we have a 50mm increase in the water content hence we have to increase the water content by 6 %.

Water content for 100 mm slump

=186+(0.06*186)=197.16 litre.

Since superplasticizers are used water content can be reduced to get good strength of concrete.

Percentage of Reduction in water content = 20%

=198 – (0.20*198)=157.73

Adopted water content =160 litre.

6.Calculation of cement and fly ash content.

Adopted water cement ratio =0.45

Total Cementitious (Cement +Fly ash) requirement

=Water Content / WaterCement ratio=160/0.45=355.55 kg.

Since Fly ash is used the amount of Cementitious content (Cement+Fly ash) shall be increased to get good workability and strength. the percentage of increase depending on experience and research. Here we increased the cementitious content by 1.1 %

Final Cementious Content (Cement+Fly ash)= 356*1.1=391.6 kg

Minimum Cement Content required for severe exposure is 340 kg

Adopted cement content =391.6 kg

391.6 kg > 340 kg ...Hence Ok.

Fly ash content ,30% replacement

391.6*0.30=117.48 ~118 kg

Cement Content requirement =Cementious content – Fly ash

= 391.6-117.48=274.12.

Calculation of Super Plasticiers 0.6 percent to the mass of cementitious content = = 391.6*(0.6/100) = 2.35 kg.

7.Coarse and Fine aggregate.

Coarse aggregate ratio = 0.62

Coarse Aggregate ratiofor 0.45 w/c ratiov = 0.63.

Final Fine Aggregate ratio = 1-0.63) = 0.37

8.Mix Calculations

Volume of concrete = 1 cu.m

Volume of Cement = Mass of Cement/(Specific Gravity*1000)

=275/(3.15*1000) =0.087 cu.m.

Total Volume of Fly ash = Flyash/(Specific Gravity*1000)

=118/(2.5*1000) = 0.041 cu.m.

Volume of Water =Water /(Specific Gravity*1000)

= 160/(1*1000)= 0.160 cu.m.

Volume of Superplasticizers = Superplasticizers /(Specific G*1000)

= 2.35/(1.12*1000)=0.002 cu.m.

Total Aggregates requirement= a – (b+c+d+e)

=1 -(0.087 +0.041+0.160+0.002)=0.71 cu.m.

Coarse Aggregate (C.A) = F * Coarse.Agg ratio *

Specific Gravity*1000

= 0.71*0.63 *2.74 *1000= 1225.6 kg

Fine Aggregate (F.A)=F * Fine Agg ratio * Specific Gravity * 1000

= 0.71*0.37*2.74 *1000=719.8 kg.

9.

S.No. Materials Quantity
1 Cement 275 kg/cu.m
2 Flyash 118 kg/cu.m
3 Fine Aggregate 720 kg/cu.m
4 Coarse Aggregate (20mm) 1226 kg/cu.m
5 WATER 160 L/cu.m
6 PCE based SuperPlasticizer 2 L

Therefore Mix Ratio of M35 Grade concrete by weight is Cement : Flyash: F.A : C.A : Water = 1:0.4:2.6:4.46:0.58.

2.Concrete Mix design for M50 grade concrete.

1.Stipulations for proportioning

A Grade Designation M50
B Type of Cement OPC 53
C Exposure Condition Extreme
D Maximum Nominal
Size of Aggregate
20mm
E Minimum Cement Content 360kg IS 456
F Maximum Cement Content 450kg As per code
G type of aggregate Crushed angular aggregate. as per requirement
H Maximum W/C ratio 0.35 IS 456
I Workability 50-75mm
J Chemical Admixture Super Plasticizer

2.Test data for materials

Specific gravity of cement : 3.12

Specific gravity of Coarse Aggregate : 2.74

Specific gravity of Fine Aggregate : 2.56

3.Target strength for mix proportions

Fck= fck+1.65*S

Value of standard deviation(s) for different grade of concrete is taken from in Table 1 of IS456.

Fck =45+1.65*5=58.25 N/mm^2.

4.Selection of water ceement ratio

From Table 5 of IS -456,

Maximum water-cement ratio = 0.35

Adopted water cement ratio =0.35.

5.Selection of water content.

From Table 2 of IS 456, maximum water content =186 litres (for 25 to 50 mm slump range) for 20 mm aggregate.

Estimated water content for 100 mm slump

=186+(6/100) x 186 =197 litres.

Based on trials with Super plasticizer water content reduction of 27% has been achieved, Hence the arrived water content

= 197 – [197 x (27/100)] = 143 litres.

6.Calculation of cement content.

Water-cement ratio = 0.35

Cement content = 143/0.35 = 410 kg/m3

From Table 5 of IS 456, minimum cement content for ‘Extreme exposure’ condition = 360 kg/m3

410 kg/m3 > 360 kg/m3, hence, O.K.

7.Coarse and Fine aggregate.

For pumpable concrete, these values should be reduced by 10 percent.

Therefore, volume of coarse aggregate = 0.65 x 0.9 =0.585

Volume of fine aggregate content =1 – 0.585=0.415.

8.Mix Calculations

Volume of concrete = 1m3

Volume of cement = (Mass of Cement/ Its Specific Gravity ) X (1/1000)

= (410/3.12) X (1/1000)

= 0.131 m3

Volume of Water = (Mass of water/specific gravity of water) X (1/1000)

= (143/1) X (1/1000)

= 0.143 m3

Volume of Superplasticizer = (Mass of Superplasticizer / Specific gravity of admixture) X (1/1000)

= (8.2/1.145) X (1/1000)

= 0.007 m3

Volume of all aggregate = (a – (b + c + d))

= 1 – (0.131 + 0.143+0.007)

= 0.719 m3

Mass of coarse aggregate = Volume of All Aggregate X Volume of Coarse Aggregate X Specific Gravity of Coarse Aggregate X 1000

= 0.719 x 0.585 x 2.74 x 1000

= 1152.48 kg

Mass of fine aggregate = Volume of all aggregate X volume of fine aggregate X Specific gravity of fine aggregate X 1000

= 0.719 x 0.415 x 2.56 x 1000

= 763.86 kg

9.

S.No. Materials Quantity
1 Cement 410 kg/m^3
2 Water 143 L/m^3
3 Fine Aggregate 763.86 kg/m^3
4 Coarse Aggregate (20mm) 1152.48 kg/m^3
5 Water Cement ratio 0.35
6 Super Plasticizer 7 L

Mix proportion by weight 1:2.30:4.60

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