Project on Concrete Mix Design for various grades of Concrete

1. Mix design for M35

1. Target strength fck = fck + 1.65s.

F`ck = 35 + 1.65×5

F`ck = 43.25

2. W/c ratio = 0.45

3. Water content = 186 litres

4. Cement content = water content/ w/c ratio

Cement content = 186/.45 = 413.333

5. Volume of coarse aggregate per unit of fine aggregate = 0.62

6. Fine aggregate= 1-0.62 = 0.38

Mix porportion

Volume of concrete = 1 m^3 ....(a)

Volume of cement = mass of cement / specific gravity of cement×1000

Volume of cement= 394.75/3.15×1000

Volume of cement= 0.126m^3 ......(b)

Volume of water = mass of water / specific gravity of water ×1000

Volume of water = 186/1×1000 = 0.186. .....(c)

Volume of aggregate= a-(b+c) = 1-(0.126+0.186)=0.688m^3

Volume of coarse aggregate= D×sg of coarse aggregate× volume of coarse aggregate×1000= 0.688×2.7×0.62×1000= 1151.7kg

Volume of fine aggregate = D× sg of fine aggregate× volume of fine aggregate×1000 = 0.688×2.65×0.38×1000= 692.82 kg

Mix design

Weight of cement = 413.333kg

Weight of fine aggregate = 1151.7kg

Weight of coarse aggregate= 692.82kg Mix design of cement= 413.333/413.333=1

Mix design of fine aggregate= weight of fine aggregate/weight of cement = 692.82/413.333= 1.68

Mix design of course aggregate = weight of coarse aggregate/weight of cement= 1151.2/413.333 = 2.78

Mix design for M35 is 1:1.68:2.78