Challenge

Project on Concrete Mix Design for various grades of Concrete

Concrete Mix Design for M35 grade coincrete with flyash

1.Targeted Mean Strength

f'ck = fck +1.65s

f'ck= 35+(1.65*5)

=43.25N/mm2

2.max Water cement ratio as per IS 456,

0.45 therefore adopt .34

3.Max water content =186 litres/cum adapt the same

Water content as per slump 120mm =201 litre

water content after admixture 1% adding=156 litre

4. calculation of cement

a.water cement ratio =.34

b.water content =156 litre/cum

c.cement +flyash =460kg/cum

d.flyash 50%=230.00kg/cum

e.cement= 230kg/cum

5.Propotion of aggregate

a.volume of coarse aggregate as per IS 10262-2019=0.62

b.Volume of Fine aggregate =0.38

6. Mix Design calculation

a. Volume of cement =mass of cement/sp. gravity of cement/1000=0.073cum

b.volume of fly ash =mass/sp. gravity/1000=.089cum

c.volume of water=0.15640cum

d.Volume of chemical=0.00387cum

e.Volume of all in aggregate=0.667cum

f.mass of 20mm=694kg

g.mass of 10mm =441kg

h. mass of sand (F.A)=683kg

i.Sp. gravity of admixture=1.19

j.Sp. gravity of flyash =2.57

Calculation of design mix for M50 concrete without fly ash

Grade of cement = OPC 043

sp. gravity of cement = 3.15

sp. gravity of sand =2.61

sp. garvity of 20mm = 2.65

sp. gravity of 10mm = 2.66

1. Targeted Mean strength

f'ck = 58.25N/mm2 for M50

2.Cement & water calculation

a.Min. Cement =400kg/cum as per IS 10262

b.water cement ratio =0.45 assume 0.35

c. water content as per IS 10262 = 180 kg/cum

d.Due to admixture , water content (20% deduct)=180*0.8=144 kg/cum

e.cement content=0.35/144=412kg/cum

3.Fine aggregate and Coarse aggregate calculation

a.Vol. of concrete = 1 cum

b.vol. of cement = 412/(3.15*1000)=0.1308 cum

c. vol. of water = 144/(1*1000)=0.1440 cum

d.vol. of admixture = 4.994 /(1.145/1000)=0.0043cum

e.vol. of other materials except F.A & C.A =(0.1308+0.1440+0.0043)=0.2791

f. vol of F.A & C.A=1-0.2791=0.7209 cum

g.vol. of F.A = 0.7209*33%=0.2379 cum (assume 33% )

h.vol. of C.A = 0.7209-0.2379=0.4830 cum

i. Mass of Fine Aggregate= 0.2379*2.61*1000=621kg/cum

j.Mass of Coarse aggragate= 0.4830*2.655*1000=1284 kg/cum

k.20mm:10mm=0.55:0.45 we adopt the ratio

then mass of 20mm=706kg

Mass of 10mm= 578 kg

l.Mass of admixture(1.2% of cement)=5.064 litre / cum

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