Project
Question 1:
Potential energy = mgh 1058.4 J
Potential energy*2 = kinetic energy
1058.4*3 = 1.2*9.8*h
H = 270m
Question 2: -
Question 3:
1/R = (1/30)+(1/60) = 0.05
Equivalent resistance = 20Ω
Question 1:
Potential energy = mgh 1058.4 J
Potential energy*2 = kinetic energy
1058.4*3 = 1.2*9.8*h
H = 270m
Question 2: -
Question 3:
1/R = (1/30)+(1/60) = 0.05
Equivalent resistance = 20Ω