Project 2

1. WATER CURRENT FORCES

K = 0.66 since circular

v= 2.5m/s river velocity

P = 52 K `v^2` = 52 x 0.66 x `2.5^2` = 214.5 kN/m2 x `pi xx r` = `pi xx 0.75^2` = 214.5x 1.767

P `approx` 380 kN/m

2. CENTRIFUGAL FORCE

Since there is no curvature R =0

no cebtrifugal resisntace required

3. WAVE LOAD

Fv* = `gamma` x `DeltaZv`x Av

`DeltaZv` = `bary` + crest ht = 1.6/2 + 8.5 = 0.8 + 8.5 = 9.3m

Av = 10.5 x 40 = 420m2

unit wt of water = 10kN/m^3

Fv* = 10 x 9.3 x 420 = 39060kN

Fvmax = Cvav x Fv* = assuming Cvav = 3 = 3 x 39060 = 117180kN

4. SNOW LOAD

d= 1250kN

B<30

So = asuuming wet snow = `gamma` x A = 8 x 3.5 x 10 = 280kN/m

S = `mu` x So = 0.8 x 280 = 224kN/m

where `mu` = 0.8 since B<30

5. TEMPERATURE LOAD

is done for 45`circ`C

6. COLLISION LOAD

KE = 500 x Ch x W x `V^2`