Challenge

Project-1: Powertrain for aircraft in runways

Answer 1:

Aircraft Empty Weight Max Fuel Weight Max Cargo Weight Max Gross Takeoff Weight
Antanov AN-225 628,000 lbs
285,000 kg
661,400 lbs
300,000 kg
417,000 lbs
190,000 kg
1,411,000 lbs
640,000 kg
Airbus A380-800 611,000 lbs
277,000 kg
560,000 lbs
254,000 kg
185,000 lbs
84,000 kg
1,268,000 lbs
575,000 kg
Boeing 747-800 485,300 lbs
220,100 kg
427,400 lbs
194,000 kg
295,000 lbs
134,000 kg
987,000 lbs
447,700 kg
Airbus A340-500 370,000 lbs
168,000 kg
386,300 lbs
175,000 kg
119,000 lbs
54,000 kg
820,000 lbs
372,000 kg
Boeing 777-300ER 370,000 lbs 168,000 kg  320,800 lbs 145,500 kg 148,000 lbs
67,100 kg
776,000 lbs
352,000 kg
Boeing 787-10 299,000 lbs 135,500 kg 223,500 lbs
101,500 kg
126,300 lbs 57,300 kg 560,000 lbs
254,000 kg
Boeing 737-900 98,500 lbs
44,700 kg
53,100 lbs
24,000 kg
44,600 lbs
20,200 kg
187,000 lbs
85,000 kg
Airbus A320-100 93,900 lbs
42,600 kg
48,700 lbs
22,100 kg
44,000 lbs
20,000 kg
150,000 lbs
68,000 kg
Embraer 190 63,500 lbs
28,800 kg
28,600 lbs
13,000 kg
28,800 lbs
13,100 kg
106,000 lbs
48,000 kg
Gulfstream G650 54,000 lbs 24,500 kg 48,200 lbs 21,900 kg 6,500 lbs
3,000 kg
100,000 lbs
45,200 kg
Bombardier CRJ900 48,160 lbs 21,850 kg 19,600 lbs 8,900 kg 6,075 lbs 2,760 kg 80,500 lbs
36,500 kg
Bombardier Q400 39,300 lbs
17,800 kg
11,700 lbs
5,300 kg
18,700 lbs
8,500 kg
62,000 lbs
28,000 kg
Learjet 75 13,900 lbs 6,300 kg 6,060 lbs
2,750 kg
2,900 lbs
1,300 kg
21,500 lbs
9,700 kg
Cessna Citation CJ4 10,300 lbs 4,700 kg 5,800 lbs
2,650 kg
2,200 lbs 1,000 kg 17,200 lbs
7,800 kg
Beechcraft King Air B100 7,100 lbs 3,200 kg 3,200 lbs
1,450 kg
4,150 lbs
1,900 kg
12,000 lbs
5,400 kg
Diamond DA50 RG  3,200 lbs
1,450 kg
340 lbs
155 lbs
1,250 lbs
560 kg
4,400 lbs
2,000 kg
Beechcraft Bonanza G36 2,500 lbs 1,150 kg 450 lbs
200 kg
850 lbs
385 kg
3,660 lbs
1,660 kg
Cessna 206H  2,200 lbs
990 kg
520 lbs
235 kg
1,150 lbs
520 kg
3,600 lbs
1,630 kg
Sirrus SR22 2,250 lbs 1,000 kg 485 lbs
220 kg
950 lbs
430 kg
3,600 lbs
1,630 kg
Cessna 172R 1,700 lbs
770 kg
380 lbs
170 kg
560 lbs
255 kg

2,425 lbs
1,100 kg

Answer 2:

Airspeed:

True airspeed is  the speed at which an aircraft is moving relative to the air it is flying in. As such, it’s also the speed at which the air is flowing around the aircraft’s wings. airspeed is what determines whether there is enough airflow around an aircraft to make it fly,

Ground:

Ground speed, on the other hand, is the aircraft’s speed relative to the ground. One thing that should be noted here is that it’s its horizontal rather than vertical speed – an aircraft climbing completely vertically would have a ground speed of zero.Ground speed is what determines how fast an aircraft will get to its destination.

Answer 3:

Aircraft towing equipment is typically used for the towing and pushback process to avoid some of the significant hazards posed by aircraft engines. When an aircraft's engine is activated, the thrust can create a high-speed wind that can easily cause damage to the airport terminal, surrounding ground vehicles, jetway, baggage and most importantly, ground personnel.

Suppressing the use of engines is especially important when towing a large aircraft, as their more powerful thrust capabilities can become exceedingly dangerous. Engine thrust can easily send any loose items airborne, turn the tiniest grains of dust into hazardous projectiles and create debris that can cause damage to multi-million dollar engines. Additionally, aircraft engines consume a great deal of fuel and generate extreme noise that can be harmful to ground personnel. Using a pushback tug for aircraft is simply a more economical and safer option than running the engines.

Answer 4:

is the movement of an aircraft on the ground, under its own power, in contrast to towing or push-back where the aircraft is moved by a tug. The aircraft usually moves on wheels, but the term also includes aircraft with skis or floats  (for water-based travel).

The power for taxiing comes from the engines itself. If it is a propeller powered aircraft, the propeller provides thrust and pulls the aircraft, like it would in air. If it is a jet engine, the exhaust air that comes out of the engine creates a forward force due to Newton's third law and moves the airplane.

Airliners have nose wheel steering, controlled by a cockpit control called a tiller. The tiller allows nose wheel to rotate at quite extreme angles making tighter turns possible. It also reduces the fuel consumption as you do not need much engine power during taxiing. If rudders were used, the power has to be increased to make sure sufficient air flows over the rudder surface to make it effective.

Once on the take off roll and the airplane gains sufficient speed i.e. enough air flows over the rudders, pilots go back to using the rudder pedals to maintain the centre line.

Some large airplanes with multi wheel main gears have a tendency to scrub the tyres on the tarmac when nose wheel is steered. To counter this problem, an automatic main gear steering is inbuilt in the aircraft. This makes the main gears turn the opposite direction to that of the nose wheel, greatly decreasing the wear on the tyres.

Answer 5:

Take off power:

T – Thrust of propulsion system pushing aircraft along runway.

D – Aerodynamic Drag of vehicle resisting the aircraft motion.

F – Rolling resistance friction due to the contact of wheels or skids on the ground.

During take-off run the imbalance in these forces will produce an acceleration along the runway.

dv/dt =  T - D - F /m

The procedure for take-off will be that the vehicle will accelerate until it reaches a safe initial flying speed. The pilot can then rotate the vehicle to an attitude to produce climb lift and it will ascend from the ground. The determination of this safe flying speed or rotation speed, VR, is a critical factor in determining take-off performance.

For safety reasons VR is usually determined as being 1.1 × VSTALL

VSTALL :  is the lowest speed that the aircraft can be flown before the airflow starts to separate from wings as the angle of attack becomes too great. The wing is assumed in this case to be in take-off configuration or "clean".

It can be calculated based on knowledge of the aircraft take-off configuration and hence the maximum achievable lift coefficient CL(max). As shown in the previous section , to maintain level flight the lift produced must equal the weight, hence the stall speed can be calculated as,

rolling resistance:

Rolling resistance, sometimes called rolling friction or rolling drag, is the force resisting the motion when a body (such as a ball, tire, or wheel) rolls on a surface. It is mainly caused by  effects; thnon elastic at is, not all the energy needed for deformation (or movement) of the wheel, roadbed, etc., is recovered when the pressure is removed. Two forms of this are hysterisis losses , and permanent plastic deformation of the object or the surface (e.g. soil). Another cause of rolling resistance lies in the slippage between the wheel and the surface, which dissipates energy. 

The rolling resistance can be expressed as

Fr = c W                                   (1)

where

Fr = rolling resistance or rolling friction (N, lbf)

c = rolling resistance coefficient - dimensionless (coefficient of rolling friction - CRF)

W = m ag

    = normal force - or weight - of the body (N, lbf)

m = mass of body (kg, lb)

ag = acceleration of gravity (9.81 m/s2, 32.174 ft/s2)

The rolling resistance for the air plane can be calculated as : 

Fr = c mr ag                                  (1)

where

Fr = rolling resistance (N, lbf)

c = rolling resistance coefficient

mr = rolling mass (kg, lbm)

ag = acceleration of gravity (9.81 m/s2)

The friction force for the puller can be calculated to

Ff = μ W

   = μ mf ag                      (2)

where

Ff = frictional force (N, lb)

μ = friction coefficient

W = weight (N, lbf)

mf = friction mass (kg)

Tire pressure:

An aircraft tire or tyre is designed to withstand extremely heavy loads for short durations. The number of tires required for aircraft increases with the weight of the aircraft, as the weight of the airplane needs to be distributed more evenly. Aircraft tire tread patterns are designed to facilitate stability in high crosswind conditions, to channel water away to prevent hydroplaning, and for braking effect.

Aircraft tires also include fusible plugs (which are assembled on the inside of the wheels), designed to melt at a certain temperature. Tires often overheat if maximum braking is applied during an aborted takeoff or an emergency landing. The fuses provide a safer failure mode that prevents tire explosions by deflating in a controlled manner, thus minimizing damage to aircraft and objects in the surrounding environment.

Answer 6A:

The various forces are airdrag force and rolling resistance force

Rolling resistance force is given by Frr=m*g*urr

                              where m-mass 

                              g= acceleration due to gravity

                              urr- rolling resistance constant

Air drag force is given by Fad = (1/2) * ρ *  V^2 * A * (Cdt + Cda)

                             where ρ=air density

                             V=velocity

                             A= frontal area

                            Cdt- airdrag coefficient of towing vehicle 

                            Cda-airdrag coefficient of aircraft

Total force Ft=Fad+Frr

Assume 

mass of towing vehicle=45000 kg

mass of aircraft =177700 Kg

Total mass=222700kg

frontal area of towing vehicle (A)=30m2

on concrete urr=0.013

g=9.8

Cdt=0.5

Cda=0.045

Velocity V=20km/h=5.88m/s

ρ=1.225kg/m3

So rolling resistance force frr=0.013*222700*9.8=28372N

Air drag force=1/2*30*1.225*5.88*5.88*0.545=346.24N

Total force Ft=28732+346.24=28718.24N

So required power =F*v=28718.24*5.88=166895W=168KW

Answer 7:

Based on the calculations done in 6A.

Force required to push/pull the aircraft =28.71 KN

Power required =168 kw

Let us assume,

The radius of tyre =25inches =0.635m

Gear ratio=8

Transmission Effeciency (nt) =87%

Motor Efficiency (nm)=95%

then,

Torque required for the wheels (Tw)=Total Force *Radius in meters

=28.71 *0.635

=18.23KNm

Motor Torque-Wheel torque/(Gear ratio'nt)

=18.23/(8*0.87)

=2.61 KNm
For nm =95%. The required motor Torque (Tm)= 1.778/0.95 =2.75kNm

Similarly. The total power required by the motor considering all the efficiencies (Pt) = 168/(0.87*0.95)=205Kw

Let us assume the towing operation was done for a 15 minutes (0.25Hrs) duration.

Then, Total Energy consumed = 205* 0.25=51 KWh

If we consider the battery capacity=220 kw is used by the towing vehicle then. The duty cycle range to control the speed from O to max speed (3m/s) is given as

Duty Cycle (d)= (Required Power)/ (Rated power)= 168/220 =0.93

Therefore the controller will be able to provide a duty cycle ranging from 0 to 93% in order to control the towing speed.

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