Project 1 - Interfacing a 16*2 LCD with Arduino using I2C protocol

1)answer

#include<LiquidCrystal.h>
#include<Wire.h>
LiquidCrystal lcd(2,3,4,5,6,7);
void setup()
{
lcd.begin(16,2); //Initializing LCD display
lcd.setCursor(0,0);
lcd.print("Starting"); //Prints STARTING in LCD
lcd.setCursor(0,1); //Sets Cursor at second line of Display
lcd.print("I2C 1 ARDUINO"); //Prints I2C ARDUINO in LCD
delay(5000); //Delay for 5 seconds
lcd.clear(); //Clears LCD display
Serial.begin(9600); //Begins Serial Communication at 9600 baud rate
Wire.begin(); //Begins I2C communication at pin (A4,A5)
}
void loop()
{
Wire.requestFrom(8,1);
byte MasterReceive = Wire.read();
int potvalue = analogRead(A0); // Reads analog value from POT (0-5V)
byte MasterSend = map(potvalue,0,1023,0,127); //Convert digital value (0 to 1023) to (0 to 127)
Wire.beginTransmission(8);
Wire.write(MasterSend);
Wire.endTransmission(); // stop transmitting
lcd.setCursor(0,0); //Sets Currsor at line one of LCD
lcd.print(">> Master <<");
lcd.setCursor(0,1);
lcd.print("SlaveVal:"); //Prints SlaveVal: in LCD
lcd.print(MasterReceive);
//lcd.print(analogRead(A0));
Serial.println("Master Received From Slave");//Prints in Serial Monitor
Serial.println(MasterReceive);
delay(500);
lcd.clear();
}