Challenge

Project 1 - Creation of user defined data type to implement the user interfaces for working with ‘Set’ (Mathematical Set theory) using Linked List

In this project, interfaces for mathematical Set Theory are implemented using C programming language. User can give the input like two list of data and this program will give the output as the union and intersection of these two lists

// C program to find union

// and intersection of two unsorted

// linked lists

#include <stdbool.h>

#include <stdio.h>

#include <stdlib.h>

/* Linked list node */

struct Node {

int data;

struct Node* next;

};

/* A utility function to insert a

node at the beginning ofa linked list*/

void push(struct Node** head_ref, int new_data);

/* A utility function to check if

given data is present in a list */

bool isPresent(struct Node* head, int data);

/* Function to get union of two

linked lists head1 and head2 */

struct Node* getUnion(struct Node* head1,

struct Node* head2)

{

struct Node* result = NULL;

struct Node *t1 = head1, *t2 = head2;

// Insert all elements of

// list1 to the result list

while (t1 != NULL) {

push(&result, t1->data);

t1 = t1->next;

}

// Insert those elements of list2

// which are not present in result list

while (t2 != NULL) {

if (!isPresent(result, t2->data))

push(&result, t2->data);

t2 = t2->next;

}

return result;

}

/* Function to get intersection of

two linked lists head1 and head2 */

struct Node* getIntersection(struct Node* head1,

struct Node* head2)

{

struct Node* result = NULL;

struct Node* t1 = head1;

// Traverse list1 and search each element of it in

// list2. If the element is present in list 2, then

// insert the element to result

while (t1 != NULL) {

if (isPresent(head2, t1->data))

push(&result, t1->data);

t1 = t1->next;

}

return result;

}

/* A utility function to insert a

node at the beginning of a linked list*/

void push(struct Node** head_ref, int new_data)

{

/* allocate node */

struct Node* new_node

= (struct Node*)malloc(sizeof(struct Node));

/* put in the data */

new_node->data = new_data;

/* link the old list of the new node */

new_node->next = (*head_ref);

/* move the head to point to the new node */

(*head_ref) = new_node;

}

/* A utility function to print a linked list*/

void printList(struct Node* node)

{

while (node != NULL) {

printf("%d ", node->data);

node = node->next;

}

}

/* A utility function that returns true if data is

present in linked list else return false */

bool isPresent(struct Node* head, int data)

{

struct Node* t = head;

while (t != NULL) {

if (t->data == data)

return 1;

t = t->next;

}

return 0;

}

/* Driver program to test above function*/

int main()

{

/* Start with the empty list */

struct Node* head1 = NULL;

struct Node* head2 = NULL;

struct Node* intersecn = NULL;

struct Node* unin = NULL;

/*create a linked lists 10->15->5->20 */

push(&head1, 20);

push(&head1, 4);

push(&head1, 15);

push(&head1, 10);

/*create a linked lists 8->4->2->10 */

push(&head2, 10);

push(&head2, 2);

push(&head2, 4);

push(&head2, 8);

intersecn = getIntersection(head1, head2);

unin = getUnion(head1, head2);

printf("\n First list is \n");

printList(head1);

printf("\n Second list is \n");

printList(head2);

printf("\n Intersection list is \n");

printList(intersecn);

printf("\n Union list is \n");

printList(unin);

return 0;

}

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