Challenge

Project 1 - Creation of user defined data type to implement the user interfaces for working with ‘Set’ (Mathematical Set theory) using Linked List

#include

#include

#include

// Link list node

struct Node {

    int data;

    struct Node* next;

};

//function declaration

void push(struct Node** head_ref, int new_data);

int isPresent(struct Node* head, int data);

// Function to get union of two linked lists head1 and head2

struct Node* getUnion(struct Node* head1, struct Node* head2)

{

    struct Node* result = NULL;

    struct Node *t1 = head1, *t2 = head2;

    // Insert all elements of list1 to the result list

    while (t1 != NULL)

    {

        push(&result, t1->data);

        t1 = t1->next;

     }

    // Insert those elements of list2 which are not present in result list

    while (t2 != NULL)

    {

        if (!isPresent(result, t2->data))

        {

            push(&result, t2->data);

        }

        t2 = t2->next;

    }

    return result;

}

// Function to get intersection of two linked lists head1 and head2

struct Node* getIntersection(struct Node* head1, struct Node* head2)

{

    struct Node* result = NULL;

    struct Node* t1 = head1;

    // Traverse list1 and search each element of it in list2. If the element is present in list 2, then insert the element to result

    while (t1 != NULL)

    {

        if (isPresent(head2, t1->data))

        {

            push(&result, t1->data);

        }

        t1 = t1->next;

    }

    return result;

}

// A utility function to insert a node at the beginning of a linked list

void push(struct Node** head_ref, int new_data)

{

    // allocate node

    struct Node* new_node = (struct Node*)malloc(sizeof(struct Node));

    // put in the data

    new_node->data = new_data;

    // link the old list off the new node

    new_node->next = (*head_ref);

    // move the head to point to the new node

    (*head_ref) = new_node;

}

// function to print a linked list

void printList(struct Node* node)

{

    while (node != NULL)

    {

        printf("%d ", node->data);

        node = node->next;

    }

}

// function that returns true if data is present in linked list else return false

int isPresent(struct Node* head, int data)

{

    struct Node* t = head;

    while (t != NULL)

    {

        if (t->data == data)

        {

            return 1;

        }

        t = t->next;

    }

    return 0;

}

// Driver program to test above function

int main()

{

    int n,m,temp;

    printf("enter the value of number of value in link list(both):-");

    fflush(stdout);

    scanf("%d %d", &n, &m);

    // Starth structure pointer with the empty list

    struct Node* head1 = NULL;

    struct Node* head2 = NULL;

    struct Node* intersecn = NULL;

    struct Node* unin = NULL;

    //for loop for link list1

    for(int i=0;i

    {

        printf("Enter the value in link list1 %d:-",i);

        fflush(stdout);

        scanf("%d", &temp);

        push(&head1, temp);

    }

   //for loop for link list2

   for(int i=0;i

   {

       printf("Enter the value in link list2 %d:-",i);

        fflush(stdout);

        scanf("%d", &temp);

        push(&head2, temp);

   }

   //call the function of intersection

    intersecn = getIntersection(head1, head2);

    //call the function of union

    unin = getUnion(head1, head2);

    printf("\n First list is ");

    //function calling with structure pointer as argument

    printList(head1);

    printf("\n Second list is ");

    printList(head2);

    printf("\n Intersection list is ");

    printList(intersecn);

    printf("\n Union list is ");

    printList(unin);

    return 0;

}

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