Challenge

Project 1 - Creation of user defined data type to implement the user interfaces for working with ‘Set’ (Mathematical Set theory) using Linked List

#include
#include
#include
struct Node {
    int data;
    struct Node* next;
};
void push(struct Node** head_ref, int new_data);
 
bool isPresent(struct Node* head, int data);
 
struct Node* getUnion(struct Node* head1,
                      struct Node* head2)
{
    struct Node* result = NULL;
    struct Node *t1 = head1, *t2 = head2;
 
    while (t1 != NULL) {
        push(&result, t1->data);
        t1 = t1->next;
    }
 
    while (t2 != NULL) {
        if (!isPresent(result, t2->data))
            push(&result, t2->data);
        t2 = t2->next;
    }
 
    return result;
}
 
struct Node* getIntersection(struct Node* head1,
                             struct Node* head2)
{
    struct Node* result = NULL;
    struct Node* t1 = head1;
 
    while (t1 != NULL) {
        if (isPresent(head2, t1->data))
            push(&result, t1->data);
        t1 = t1->next;
    }
 
    return result;
}
 
void push(struct Node** head_ref, int new_data)
{
 
    struct Node* new_node
        = (struct Node*)malloc(sizeof(struct Node));
 
    new_node->data = new_data;
 
    new_node->next = (*head_ref);
 
    (*head_ref) = new_node;
}
 
void printList(struct Node* node)
{
    while (node != NULL) {
        printf("%d ", node->data);
        node = node->next;
    }
}
 
bool isPresent(struct Node* head, int data)
{
    struct Node* t = head;
    while (t != NULL) {
        if (t->data == data)
            return 1;
        t = t->next;
    }
    return 0;
}
 
int main()
{
    struct Node* head1 = NULL;
    struct Node* head2 = NULL;
    struct Node* intersecn = NULL;
    struct Node* unin = NULL;
 
    push(&head1, 20);
    push(&head1, 4);
    push(&head1, 15);
    push(&head1, 10);
 
    push(&head2, 10);
    push(&head2, 2);
    push(&head2, 4);
    push(&head2, 8);
 
    intersecn = getIntersection(head1, head2);
    unin = getUnion(head1, head2);
 
    printf("\n First list is \n");
    printList(head1);
 
    printf("\n Second list is \n");
    printList(head2);
 
    printf("\n Intersection list is \n");
    printList(intersecn);
 
    printf("\n Union list is \n");
    printList(unin);
 
    return 0;
}
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