Challenge

Project 1 - Creation of user defined data type to implement the user interfaces for working with ‘Set’ (Mathematical Set theory) using Linked List

  1. #include
    #include
    #include
    // Link list node
    struct Node {
    int data;
    struct Node* next;
    };
    //function declaration
    void push(struct Node** head_ref, int new_data);
    int isPresent(struct Node* head, int data);
    // Function to get union of two linked lists head1 and head2
    struct Node* getUnion(struct Node* head1, struct Node* head2)
    {
    struct Node* result = NULL;
    struct Node *t1 = head1, *t2 = head2;
    // Insert all elements of list1 to the result list
    while (t1 != NULL)
    {
    push(&result, t1->data);
    t1 = t1->next;
    }
    // Insert those elements of list2 which are not present in result list
    while (t2 != NULL)
    {
    if (!isPresent(result, t2->data))
    {
    push(&result, t2->data);
    }
    t2 = t2->next;
    }
    return result;
    }
    // Function to get intersection of two linked lists head1 and head2
    struct Node* getIntersection(struct Node* head1, struct Node* head2)
    {
    struct Node* result = NULL;
    struct Node* t1 = head1;
    // Traverse list1 and search each element of it in list2. If the element is present in list 2, then insert the element to result
    while (t1 != NULL)
    {
    if (isPresent(head2, t1->data))
    {
    push(&result, t1->data);
    }
    t1 = t1->next;
    }
    return result;
    }
    // A utility function to insert a node at the beginning of a linked list
    void push(struct Node** head_ref, int new_data)
    {
    // allocate node
    struct Node* new_node = (struct Node*)malloc(sizeof(struct Node));
    // put in the data
    new_node->data = new_data;
    // link the old list off the new node
    new_node->next = (*head_ref);
    // move the head to point to the new node
    (*head_ref) = new_node;
    }
    // function to print a linked list
    void printList(struct Node* node)
    {
    while (node != NULL)
    {
    printf("%d ", node->data);
    node = node->next;
    }
    }
    // function that returns true if data is present in linked list else return false
    int isPresent(struct Node* head, int data)
    {
    struct Node* t = head;
    while (t != NULL)
    {
    if (t->data == data)
    {
    return 1;
    }
    t = t->next;
    }
    return 0;
    }
    // Driver program to test above function
    int main()
    {
    int n,m,temp;
    printf("enter the value of number of value in link list:-");
    fflush(stdout);
    scanf("%d %d", &n, &m);
    // Starth structure pointer with the empty list
    struct Node* head1 = NULL;
    struct Node* head2 = NULL;
    struct Node* intersecn = NULL;
    struct Node* unin = NULL;
    //for loop for link list1
    for(int i=0;i {
    printf("Enter the value in link list1 %d:-",i);
    fflush(stdout);
    scanf("%d", &temp);
    push(&head1, temp);
    }
    //for loop for link list2
    for(int i=0;i {
    printf("Enter the value in link list2 %d:-",i);
    fflush(stdout);
    scanf("%d", &temp);
    push(&head2, temp);

    }
    //call the function of intersection
    intersecn = getIntersection(head1, head2);
    //call the function of union
    unin = getUnion(head1, head2);
    printf("\n First list is ");
    //function calling with structure pointer as argument
    printList(head1);
    printf("\n Second list is ");
    printList(head2);
    printf("\n Intersection list is ");
    printList(intersecn);
    printf("\n Union list is ");
    printList(unin);
    return 0;
    }

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