Project 1 - Creation of user defined data type to implement the user interfaces for working with ‘Set’ (Mathematical Set theory) using Linked List
program:
#include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
struct Node{
int data;
struct Node* next;
};
void push(struct Node** head_ref, int new_data);
int isPresent(struct Node* head, int data);
struct Node* getUnion(struct Node* head1, struct Node* head2)
{
struct Node* result = NULL;
struct Node *t1 = head1, *t2 = head2;
while (t1 != NULL)
{
push(&result, t1->data);
t1 = t1->next;
}
while (t2 != NULL)
{
if (!isPresent(result, t2->data))
{
push(&result, t2->data);
}
t2 = t2->next;
}
return result;
}
struct Node* getIntersection(struct Node* head1, struct Node* head2)
{
struct Node* result = NULL;
struct Node* t1 = head1;
while (t1 != NULL)
{
if (isPresent(head2, t1->data))
{
push(&result, t1->data);
}
t1 = t1->next;
}
return result;
}
void push(struct Node** head_ref, int new_data)
{
struct Node* new_node = (struct Node*)malloc(sizeof(struct Node));
new_node->data = new_data;
new_node->next = (*head_ref);
(*head_ref) = new_node;
}
void printList(struct Node* node)
{
while (node != NULL)
{
printf("%d ", node->data);
node = node->next;
}
}
int isPresent(struct Node* head, int data)
{
struct Node* t = head;
while (t != NULL)
{
if (t->data == data)
{
return 1;
}
t = t->next;
}
return 0;
}
int main()
{
int n,m,temp;
printf("enter the value of number of value in link list(both):- ");
fflush(stdout);
scanf("%d %d", &n, &m);
struct Node* head1 = NULL;
struct Node* head2 = NULL;
struct Node* intersecn = NULL;
struct Node* unin = NULL;
for(int i=0;i<n;i++)
{
printf("Enter the value in link list1 %d:-",i);
fflush(stdout);
scanf("%d", &temp);
push(&head1, temp);
}
for(int i=0;i<m;i++)
{
printf("Enter the value in link list2 %d:-",i);
fflush(stdout);
scanf("%d", &temp);
push(&head2, temp);
}
intersecn = getIntersection(head1, head2);
unin = getUnion(head1, head2);
printf("\n First list is ");
printList(head1);
printf("\n Second list is ");
printList(head2);
printf("\n Intersection list is ");
printList(intersecn);
printf("\n Union list is ");
printList(unin);
return 0;
}
OUTPUT:
Enter the value in link list2 3:-7
first list is 5 4 3
second list is 7 6 5 4
intersection list is 4 5
union list is 6 7 3 4 5