Challenge

Project 1

1. Design a multi-storey Residential Building located in Bangalore using STAAD Pro Connect Edition. The specification must be as follows:

    

Building floors

G + 6 + R

Plan dimension

B = 25m ,  L = 16m

Storey Height

h = 3.5m

Soil 

Hard soil

Use

Residential Purpose

Safe Bearing Capacity

180 kN/m2

Maximum slab thickness

150mm

Assume suitable sections for structural elements. Follow IS456, IS1893 and IS 875

Material specifications :

Assuming the size of beams = 300mmX400mm

Assuming size of columns = 300mX400mm

Assuming thickness of slab as 150mm

Load calculations:

(1) Dead loads:

(a) Dead load on floor : 

  • Dead weight due to slab = 0.15 x 25 = 3.75kN/sqm
  • Partitions = 1.5kN/sqm
  • Floor finish = 2.5kN/sqm
  • Miscellaneous = 1kN/sqm
  • Total floor load = 8.75kN/sqm

(b) Dead load on roof:

  • Dead load on roof slab = 3.75kN/sqm
  • Insulation and water proofing = 0.5kN/sqm
  • MEP services = 0.5kN/sqm
  • Miscellaneous = 0.5kN/sqm
  • Total roof load = 5.25kN/sqm

(2) Live load :

(a) For residential bilding live load for a floor is 3kN/sqm

(b) For roof the live load is 1.5kN/sqm

(c) Wind load calculation as per IS875 part-111

Design wind spedd

we know that 

Vz=Vbxk1xk2xk3xk4

Where,

Vb is basic wind speed (m/s)

k1 is reisk coefficent (IS 875 part-111 Table -1)

k2 is terrain roughness and height factor

k3 is topograhpy factor (IS 875 part-111 Clause 6.3.3)

k4 is importance factor for cyclic region

Vb = 33m/s ,for Bangalore (as per IS875 part-111)

k1 = 1

k2 = 1.15 (for height of 23m)

k3 = 1

k4 = 1

therefore , Vb = 33x1x1.15x1x1 

Vb = 37.95m/s

Wind pressure (Pz) :

Pz = 0.6x (Vz)^2

Pz = 0.6 x (3.795)^2

Pz = 864.121N

Pz = 0.864kN

Similarly, we can calculate the wind pressure for different heights like below

Height (m) k1 k2 k3 k4 Vz Pz Pz in kN
3.5 1 1.05 1 1 34.65 720.37 0.72
7 1 1.05 1 1 34.65 720.37 0.72
10.5 1 1.06 1 1 35.2 743.42 0.74
14 1 1.08 1 1 35.64 762.12 0.76
17.5 1 1.1 1 1 36.3 790.61 0.79
21 1 1.125 1 1 37.13 827.18 0.83
24.5 1 1.13 1 1 37.29 834.32 0.83

 

(d) Seismic load :

Design base shear :

Vb =Ah x W

where,

Ah = Horizontal coefficient of accelaration

W = seismic weight

As we know that Ah can be calculated by formula

so, as the given location is bangalore

Seismic zone(Z) = Zone ii

Soil type(Sa) = Hard soil

Importance factor = 1 for residential building

Response reduction factor = 5

Calculation of Sa/g (design accelaration co-efficient for different soil types :

where, 

h = height of the building

d = base dimension of the building at the plinth level along the consideration direction of earthquake shaking in m

Along X direction

Tx =0.09x23/4

T = 0.52 s

Along Z direction 

Tz = 0.09x23/5

T = 0.41 s

Considerting the maximum time period, T = 0.52 s.

According to the IS code for hard soil whose T valueis between 0.4s to 4s , the value for Sa/g = 1.47 

Sa/g = 1/T = 1.47

For reduction factor (R)

R = 5

I is importance factor, I = 1

Now, Ah = (0.1/2) x 1.47 x (1/5)

Ah = 0.0147

Seismic weight of building :

  • Dead and live load calculations for all floors

 

       area of each floor = 16x25 = 400sqm

  • Typical floor weight due to dead load 

         DL = 8.75KN/sqm

        so total dead load for each floor = 8.75 x 400 = 3500kn

         DL due to roof = 5.25 x 400 = 2100kN

  • Due to live load

         floor load LL = 3kN/sqm, which is reduced by 50% due to addition of seismic load

         LL = 1.5kN/sqm

       Total LL for all the floors = 1.5 x 400 = 600kN

       LL for roof is neglected according to IS code

  • Total seismic  weight W = Dl + LL + DL of roof

                                           (3500+600)x6 + 2100 = 26766kN

 

Design base shear :

Ah = 0.0147

W =  26766kN

Design base shear Vb = 0.0147x26766

Vb = 393.46 kN

lateral force at different levels :

Formula according to IS code 

storey level wi hi wihi2 ki Lateral force(Qx) Lateral force (Qz)
Roof 2100 23 1110900 0.19 74.76 74.76
fifth floor 4100 21 1808100 0.31 121.98 121.98
fourth floor 4100 17.5 1255625 0.22 86.56 86.56
third floor 4100 14 803600 0.14 55.08 55.08
second floor 4100 10.5 452025 0.07 27.55 27.55
first floor 4100 7 323900 0.06 23.61 23.61
ground floor 4100 3.5 50225 0.009 3.54 3.54
      5804375   393.46 393.46

 

Design of slab element using MS-excel

 

Bar bending schedule for beams

  • A step by step procedure for Beam design in RCDC has been shown with the help of pictures below 
  • After analysing the structure, goto advanced concrete design which is present at the left side under workflow tab
  • Select RCDC and selecr beams for a level
  • Click on create project after giving it a name
  • Now, RCDC takes all the required information from STAAD pro 
  • Noe, goto settings and give all the required settings such as grade of steel and concreet, clear cover etc
  • Now, goto design tab and click on design
  • A detailed design of beams can be seen and all the failed beams are shown with a red mark
  • Calculations and others can be extracted from Reports tab
  • Bar bending schedule can be extracted from BBS tab

  • There were some failed beams in the structure 
  • So the dimensions are changed to make the structure pass the forces applied 
  • Revised structure is analised and the same procedure as shown above is perfoemed once again and BBS of all passed beams have been extracted.

 

Bar bending schedule for columns

  • A step by step procedure for column design in RCDC has been shown with the help of pictures below 
  • After analysing the structure, goto advanced concrete design which is present at the left side under workflow tab
  • Select RCDC and select columns and walls 
  • Click on create project after giving it a name
  • Now, RCDC takes all the required information from STAAD pro 
  • Noe, goto settings and give all the required settings such as grade of steel and concreet, clear cover etc
  • Now, goto design tab and click on design
  • A detailed design of columns can be seen and all the failed columns are shown with a red mark
  • Calculations and others can be extracted from Reports tab
  • Bar bending schedule can be extracted from BBS tab

 

 

Design of foundations using STAAD pro

  • A step by step procedure for foundation design in STAAD pro has been shown with the help of pictures below 
  • After analysing the structure, goto foundation design which is present at the left side under workflow tab
  • Select RCDC and select columns and walls 
  • Now, foundation design connect takes all the required information from STAAD pro 
  • Now, goto units and change tothe required units and give all the required specifications such as grade of steel and concreet, clear cover etc
  • Now, goto design in the main navigator bar present at the left side of the screen
  • A detailed design of foundation can be seen 
  • Detailed and schedule drawings, General arrangement drawing and calculation sheets can be extracted from the tab above the working screen

 

Result : 

A residential building of G+6+R has been designed successfully using STAAD pro, RCDC and STAAD foundation connect and all the reports such as calculations are added in the documents section including the STAAD pro file.

 

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